Checking for uniqueness in an array in JavaScript

We are required to write a JavaScript function that takes in an array of numbers as the first and the only argument. The function should return true if all the numbers in the array appear only once (i.e., all the numbers are unique), and false otherwise.

For example −

If the input array is −

const arr = [12, 45, 6, 34, 12, 57, 79, 4];

Then the output should be −

const output = false;

because the number 12 appears twice in the array.

Example

The code for this will be −

 Live Demo

const arr = [12, 45, 6, 34, 12, 57, 79, 4];
const containsAllUnique = (arr = []) => {
   const { length: l } = arr;
   for(let i = 0; i < l; i++){
      const el = arr[i];
      const firstIndex = arr.indexOf(el);
      const lastIndex = arr.lastIndexOf(el);
      if(firstIndex !== lastIndex){
         return false;
      };
   };
   return true;
};
console.log(containsAllUnique(arr));

Output

And the output in the console will be −

false

AmitDiwan

Published on 26-Feb-2021 08:33:11

• Related Questions & Answers
• Checking for uniqueness of a string in JavaScript
• Checking an array for palindromes - JavaScript  
• JavaScript Array: Checking for multiple values
• Checking for vowels in array of numbers using JavaScript
• Checking for majority element in a sorted array in JavaScript
• Checking progressive array - JavaScript
• Checking for Fibonacci numbers in JavaScript
• Checking for coprime numbers in JavaScript
• Checking for ascending arrays in JavaScript
• Checking for straight lines in JavaScript
• Checking for convex polygon in JavaScript
• Checking for increasing triplet in JavaScript
• Checking for special numbers in JavaScript
• JavaScript - Checking for pandigital numbers
• Checking for overlapping times JavaScript