Check if items in an array are consecutive but WITHOUT SORTING in JavaScript

We are required to write a JavaScript function that takes in an array of Numbers as the first argument and a number, say n, as the second argument.

Our function should check if there is a sequence of n (taken as the second argument) or more consecutive numbers in the array but without sorting the array.

For example, if our input array is −

const arr = [0, 4, 6, 5, 9, 8, 9, 12];
const n = 3;

Then our function should return true because there exist three consecutive numbers 4, 5, and 6 in the array.

Example

The code for this will be −

const arr = [0, 4, 6, 5, 9, 8, 9, 12];
const n = 3;
const findSequence = (arr, num) => {
   if(num > arr.length){
      return false;
   };
   let count = 1;
   for(let i = 0; i < arr.length; i++){
      let el = arr[i];
      while(arr.includes(++el)){
         count++;
         if(count === num){
            return true;
         };
      };
      count = 1;
   };
   return false;
};
console.log(findSequence(arr, n));
console.log(findSequence(arr, 4));

Output

And the output in the console will be −

true
false

AmitDiwan

Published on 23-Nov-2020 09:55:23

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