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Check if an array is descending, ascending or not sorted in JavaScript
We are required to write a JavaScript function that takes in an array of Numbers. The function should check whether the numbers in the array are in increasing order, or in decreasing order or in no specific order.
If the array contains only one element then we should return a message saying not enough elements.
And if the array has all the elements equal, we should return a message saying all elements are equal.
Example
The code for this will be −
const arr1 = [7, 2, 1, 3, 2, 1];
const arr2 = [1, 1, 2, 3, 7, 7];
const determineOrder = arr => {
if(arr.length < 2){
return 'not enough items';
};
let ascending = null;
let nextArr = arr.slice(1);
for(var i = 0; i < nextArr.length; i++) {
if(nextArr[i] === arr[i]){
continue;
}else if(ascending === null) {
ascending = nextArr[i] > arr[i];
}else if (ascending !== nextArr[i] > arr[i]){
return 'unsorted';
};
}
if(ascending === null){
return 'all items are equal';
};
return ascending ? 'ascending' : 'descending';
};
console.log(determineOrder(arr1));
console.log(determineOrder(arr2));
console.log(determineOrder([1, 1, 1, 1]));
console.log(determineOrder([7, 2, 2, 1]));Output
The output in the console −
unsorted ascending all items are equal descending
Updated on: 10-Oct-2020
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