# Check If a String Can Break Another String in C++

C++Server Side ProgrammingProgramming

Suppose we have two strings s1 and s2 whose size are same; we have to check whether some permutation of string s1 can break some permutation of string s2 or vice-versa. A string a can break string b if x[i] >= y[i] (in alphabetical order) for all i in range 0 to n-1.

So, if the input is like s1 = abc and s2 = xya, then the output will be true. This is because "ayx" is a permutation of s2 that can break to string "abc" which is a permutation of s1="abc".

To solve this, we will follow these steps −

• Define a function check(), this will take s1, s2,

• for initialize i := 0, when i < size of s1, update (increase i by 1), do −

• if s2[i] < s1[i], then −

• return false

• return true

• From the main method, do the following −

• sort the array s1

• sort the array s2

• f3 := check(s2, s1)

• f4 := check(s1, s2)

• return true either f3 is true or f4 is true, otherwise false

## Example

Let us see the following implementation to get a better understanding −

Live Demo

#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
bool check(string& s1, string& s2){
for (int i = 0; i < s1.size(); i++) {
if (s2[i] < s1[i])
return false;
}
return true;
}
bool checkIfCanBreak(string s1, string s2) {
sort(s1.begin(), s1.end());
sort(s2.begin(), s2.end());
bool f3 = check(s2, s1);
bool f4 = check(s1, s2);
return f3 || f4;
}
};
main(){
Solution ob;
cout << (ob.checkIfCanBreak("abc", "xya"));
}

## Input

"abc", "xya"

## Output

1