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# Check if a number can be represented as a sum of 2 triangular numbers in C++

In this section, we will see if we can express one number as the sum of two triangular numbers or not. The triangular numbers are like below −

From the example, we can see that 1, 3, 6, 10 are some triangular numbers. We need to express a number N (say 16) as sum of two triangular numbers (6, 10).

The approach is very simple. We have to get all triangular numbers less than N. Form a set from these values. Now we have to take a number say X from the set, and check whether N – X is present in the set, then X can be represented as sum of two triangular numbers.

## Example

#include <iostream> #include <set> using namespace std; bool isSumTriangularNum(int n) { set<int> s; int i = 1; while (1) { //find and store all triangular numbers below n, and store into set int x = i * (i + 1) / 2; if (x >= n) break; s.insert(x); i++; } for (auto x : s) if (s.find(n - x) != s.end()) return true; return false; } int main() { int num = 16; if(isSumTriangularNum(num)){ cout << "Can be represented"; }else{ cout << "Cannot be represented"; } }

## Output

Can be represented

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