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Check if a given number is Pronic in C++
Here we will see, how to check whether a number is Pronic number or not. A number that can be arranged to form a rectangle, are called the pronic numbers. First few pronic numbers are: 0, 2, 6, 12, 20, 30, 42, 56, 72, 90, 110, 132, 156, 182, 210, 240, 272, 306, 342. The pronin numbers are product of two consecutive integers. So a pronic number n = x * (x + 1).
Here we will check and generate some pronic numbers.
Example
#include <iostream>
#include <cmath>
using namespace std;
bool isPronicNumber(int num) {
for (int i = 0; i <= (int)(sqrt(num)); i++)
if (num == i * (i + 1))
return true;
return false;
}
int main() {
for (int i = 0; i <= 200; i++)
if (isPronicNumber(i))
cout << i << " ";
}Output
0 2 6 12 20 30 42 56 72 90 110 132 156 182
Updated on: 22-Oct-2019
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