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Check if a given mobile number is fancy in C++
We have a 10 digit mobile number, our task is to check whether the number is fancy number or not. There are three different conditions for a fancy number. If at least one is true, then the number is fancy. These conditions are like below −
- A single number occurs three consecutive times, like 555
- Three consecutive numbers are either in increasing or decreasing order like 123 or 321.
- A single digit occurs four or more times in a number, like 8965499259, here 9 has occurred four times.
One example of fancy number is 9859009976, this is a fancy number as the third condition satisfies.
We will take the number as string, for condition three, count the frequency of each number, a basic concept of hashing is used here.
Example
#include <iostream> #define N 5 using namespace std; bool consecutiveThreeSameDigits(string s) { for (int i = 0; i < s.size() - 2; i++) { if (s[i] == s[i + 1] && s[i + 1] == s[i + 2]) return true; } return false; } bool incDecThree(string s) { for (int i = 0; i < s.size() - 2; i++) { if ((s[i] < s[i + 1] && s[i + 1] < s[i + 2]) || (s[i] > s[i + 1] && s[i + 1] > s[i + 2])) return true; } return false; } bool fourOccurrence(string s) { int freq[10]; for(int i = 0; i < 10; i++) freq[i] = 0; for (int i = 0; i < s.size(); i++) freq[s[i] - '0']++; for (int i = 0; i < 9; i++) if (freq[i] >= 4) return true; return false; } bool isFancyNumber(string s) { if (consecutiveThreeSameDigits(s) || incDecThree(s) || fourOccurrence(s)) return true; else return false; } int main() { string s = "7609438921"; if (isFancyNumber(s)) cout << "This is fancy number"; else cout << "This is not a fancy number"; }
Output
This is fancy number
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