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C# Queryable Max Method
Get the maximum value from a sequence using the Max() method.
Let’s say the following is our list.
List<long> list = new List<long> { 200, 400, 600, 800, 1000, 1200, 1400, 1600, 1800, 2000 };Use the Max() method to get the largest element.
list.AsQueryable().Max();
Example
using System;
using System.Collections.Generic;
using System.Linq;
class Demo {
static void Main() {
List<long> list = new List<long> { 200, 400, 600, 800, 1000, 1200, 1400, 1600, 1800, 2000 };
foreach(long ele in list)
Console.WriteLine(ele);
// getting largest element
long max_num = list.AsQueryable().Max();
Console.WriteLine("Largest number = {0}", max_num);
}
}Output
200 400 600 800 1000 1200 1400 1600 1800 2000 Largest number = 2000
Updated on: 23-Jun-2020
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