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C# Program to skip a specified number of elements of an array
The following is our array −
int[] points = { 210, 250, 300, 350, 420};Use skip() method to skip elements. Add the number as an argument that displays the number of elements to be returned.
IEnumerable<int> skipEle = points.AsQueryable().OrderByDescending(s => s).Skip(3);
Example
using System;
using System.Linq;
using System.Collections.Generic;
public class Demo {
public static void Main() {
int[] points = { 210, 250, 300, 350, 420};
Console.WriteLine("Initial array...");
foreach (int res in points)
Console.WriteLine(res);
IEnumerable<int> skipEle = points.AsQueryable().OrderByDescending(s => s).Skip(3);
Console.WriteLine("Skipped 3 elements...");
foreach (int res in skipEle)
Console.WriteLine(res);
}
}Output
Initial array... 210 250 300 350 420 Skipped 3 elements... 250 210
Updated on: 23-Jun-2020
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