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C# program to accept two integers and return the remainder
Firstly, set the two numbers.
int one = 250; int two = 200;
Now pass those numbers to the following function.
public int RemainderFunc(int val1, int val2) { if (val2 == 0) throw new Exception("Second number cannot be zero! Cannot divide by zero!"); if (val1 < val2) throw new Exception("Number cannot be less than the divisor!"); else return (val1 % val2); }
Above we have checked for two conditions i.e.
- If the second number is zero, an exception occurs.
- If the first number is less than the second number, an exception occurs.
To return remainder of two numbers, the following is the complete code.
Example
using System; namespace Program { class Demo { public int RemainderFunc(int val1, int val2) { if (val2 == 0) throw new Exception("Second number cannot be zero! Cannot divide by zero!"); if (val1 < val2) throw new Exception("Number cannot be less than the divisor!"); else return (val1 % val2); } static void Main(string[] args) { int one = 250; int two = 200; int remainder; Console.WriteLine("Number One: "+one); Console.WriteLine("Number Two: "+two); Demo d = new Demo(); remainder = d.RemainderFunc(one, two); Console.WriteLine("Remainder: {0}", remainder ); Console.ReadLine(); } } }
Output
Number One: 250 Number Two: 200 Remainder: 50
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