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Can MongoDB find() function display avoiding _id?
Yes, we can avoid the _id, using the following syntax in MongoDB −
db.yourCollectionName.find({},{ _id:0});Let us first create a collection with documents:>
> db.excludeIdDemo.insertOne({"CustomerName":"Larry"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd7f62c1a844af18acdffb9")
}
> db.excludeIdDemo.insertOne({"CustomerName":"Chris"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd7f6311a844af18acdffba")
}
> db.excludeIdDemo.insertOne({"CustomerName":"Mike"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd7f6351a844af18acdffbb")
}
> db.excludeIdDemo.insertOne({"CustomerName":"Bob"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd7f6381a844af18acdffbc")
}Following is the query to display all documents from a collection with the help of find() method −
> db.excludeIdDemo.find().pretty();
This will produce the following output −
{ "_id" : ObjectId("5cd7f62c1a844af18acdffb9"), "CustomerName" : "Larry" }
{ "_id" : ObjectId("5cd7f6311a844af18acdffba"), "CustomerName" : "Chris" }
{ "_id" : ObjectId("5cd7f6351a844af18acdffbb"), "CustomerName" : "Mike" }
{ "_id" : ObjectId("5cd7f6381a844af18acdffbc"), "CustomerName : "Bob" }Following is the query to exclude _id in find() −
> db.excludeIdDemo.find({},{ _id:0});This will produce the following output −
{ "CustomerName" : "Larry" }
{ "CustomerName" : "Chris" }
{ "CustomerName" : "Mike" }
{ "CustomerName" : "Bob" }
Updated on: 30-Jul-2019
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