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C program to store Student records as Structures and Sort them by Name
In this problem, we are given a student’s record which contains student_id, student_name, student_percentage. Our task is to create a C program to store student records as structure and sort them by name.
Let’s take an example to understand the problem,
Input − student record =
{{ student_id = 1, student_name = nupur, student_percentage = 98},
{ student_id = 2, student_name = Akash, student_percentage = 75},
{ student_id = 3, student_name = Yash, student_percentage = 62},
{ student_id = 4, student_name = Jyoti, student_percentage = 87},
{ student_id = 5, student_name = Ramlal, student_percentage = 80}}Output − student record =
{{ student_id = 2, student_name = Akash, student_percentage = 75},
{ student_id = 4, student_name = Jyoti, student_percentage = 87},
{ student_id = 1, student_name = nupur, student_percentage = 98},
{ student_id = 5, student_name = Ramlal, student_percentage = 80},
{ student_id = 3, student_name = Yash, student_percentage = 62}}To solve this problem, we will first create a structure that will store the details of the student. Now, we will use qsort() and in that qsort, we will define a comparator function for this qsort that will compare the names of the structure using strcmp() method.
Example
The program to store Student records as Structures and Sort them by Name
//C program to store Student records as Structures and Sort them by Name
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct Student {
int student_id;
char* student_name;
int student_percentage;
};
int comparator(const void* s1, const void* s2){
return strcmp(((struct Student*)s1)->student_name,((struct Student*)s2)->student_name);
}
int main() {
int n = 5;
struct Student arr[n];
//student 1
arr[0].student_id = 1;
arr[0].student_name = "Nupur";
arr[0].student_percentage = 98;
//student 2
arr[1].student_id = 2;
arr[1].student_name = "Akash";
arr[1].student_percentage = 75;
//student 3
arr[2].student_id = 3;
arr[2].student_name = "Yash";
arr[2].student_percentage = 62;
//student 4
arr[3].student_id = 4;
arr[3].student_name = "Jyoti";
arr[3].student_percentage = 87;
//student 5
arr[4].student_id = 5;
arr[4].student_name = "Ramlal";
arr[4].student_percentage = 80;
printf("Unsorted Student Record:
");
for (int i = 0; i < n; i++) {
printf("Id = %d, Name = %s, Age = %d
", arr[i].student_id, arr[i].student_name, arr[i].student_percentage);
}
qsort(arr, n, sizeof(struct Student), comparator);
printf("
Student Records sorted by Name:
");
for (int i = 0; i < n; i++) {
printf("Id = %d, Name = %s, Age = %d
", arr[i].student_id, arr[i].student_name, arr[i].student_percentage);
}
return 0;
}Output
Unsorted Student Record: Id = 1, Name = Nupur, Age = 98 Id = 2, Name = Akash, Age = 75 Id = 3, Name = Yash, Age = 62 Id = 4, Name = Jyoti, Age = 87 Id = 5, Name = Ramlal, Age = 80 Student Records sorted by Name: Id = 2, Name = Akash, Age = 75 Id = 4, Name = Jyoti, Age = 87 Id = 1, Name = Nupur, Age = 98 Id = 5, Name = Ramlal, Age = 80 Id = 3, Name = Yash, Age = 62
Updated on: 05-Aug-2020
2K+ Views
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