C program to remove the brackets from a given input.

Problem

Let’s create a simplified expression by removing brackets from the expressions.

Solution

Example 1

Input: A string expression with bracket is as follows:
(x+y)+(z+q)
The output is as follows:
x+y+z+q

Example 2

The input is as follows:
(x-y+z)-p+q
The output is as follows:
x-y+z-p+q

Algorithm

Refer an algorithm to remove the brackets from a given input.

Step 1: Declare and read the input at runtime.

Step 2: Traverse the string.

Step 3: Copy each element of the input string into new string.

Step 4: If anyone parenthesis is encountered as an element, replace it with empty space.

Example

Following is the C program to remove the brackets from a given input −

#include<stdio.h>
int main(){
   int i=0,c=0,j=0;
   char a[100],b[100];
   printf("
Enter the string :");
   scanf("%s",a);
   while(a[i]!='\0'){
      if((a[i]=='(') && (a[i-1]=='-')){
         (c=0)?j=i:j=c;
         while(a[i]!=')'){
            if(a[i+1]=='+')
               b[j++]='-';
            else if(a[i+1]=='-')
               b[j++]='+';
            else if(a[i+1]!=')')
               b[j++]=a[i+1];
               i++;
         }
         c=j+1;
      }
      else if(a[i]=='(' && a[i-1]=='+'){
         (c==0)?j=i:j=c;
         while(a[i]!=')'){
            b[j++]=a[i+1];
            i++;
         }
         j–;
         c=j+1;
      }
      else if(a[i]==')'){
         i++;
         continue;
      } else {
         b[j++]=a[i];
      }
      i++;
   }
   b[j]='\0';
   printf("%s",b);
   return 0;
}

Output

When the above program is executed, it produces the following output −

Enter the string:(x+y)-z
x+y-z