C program to remove the brackets from a given input.



Problem

Let’s create a simplified expression by removing brackets from the expressions.

Solution

Example 1

Input: A string expression with bracket is as follows:
(x+y)+(z+q)
The output is as follows:
x+y+z+q

Example 2

The input is as follows:
(x-y+z)-p+q
The output is as follows:
x-y+z-p+q

Algorithm

Refer an algorithm to remove the brackets from a given input.

Step 1: Declare and read the input at runtime.

Step 2: Traverse the string.

Step 3: Copy each element of the input string into new string.

Step 4: If anyone parenthesis is encountered as an element, replace it with empty space.

Example

Following is the C program to remove the brackets from a given input −

#include<stdio.h>
int main(){
   int i=0,c=0,j=0;
   char a[100],b[100];
   printf("
Enter the string :");    scanf("%s",a);    while(a[i]!='\0'){       if((a[i]=='(') && (a[i-1]=='-')){          (c=0)?j=i:j=c;          while(a[i]!=')'){             if(a[i+1]=='+')                b[j++]='-';             else if(a[i+1]=='-')                b[j++]='+';             else if(a[i+1]!=')')                b[j++]=a[i+1];                i++;          }          c=j+1;       }       else if(a[i]=='(' && a[i-1]=='+'){          (c==0)?j=i:j=c;          while(a[i]!=')'){             b[j++]=a[i+1];             i++;          }          j–;          c=j+1;       }       else if(a[i]==')'){          i++;          continue;       } else {          b[j++]=a[i];       }       i++;    }    b[j]='\0';    printf("%s",b);    return 0; }

Output

When the above program is executed, it produces the following output −

Enter the string:(x+y)-z
x+y-z

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