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C program to print name inside heart pattern using for loop.
Problem
Write a program to print heart shaped pattern with the name in centre using for loop.
Solution
The user has to enter the name that should be printed in centre along with the number of rows the stars has to be print.
Algorithm
Refer an algorithm given below to print the name in heart pattern by using for loop.
Step 1 − Declare variables.
Step 2 − Read a name at runtime that should be printed on centre.
Step 3 − Read number of rows.
Step 4 − Find the length of name.
Step 5 − Print upper part of the heart.
Step 6 − Print lower part of the heart.
Step 7 − Print the name on screen.
Example
Following is the C program to print the name in heart pattern by using for loop −
#include <stdio.h>
#include <string.h>
int main(){
int i, j, n;
char name[50];
int len;
printf("Enter your name: ");
gets(name);
printf("Enter no of rows: ");
scanf("%d", &n);
len = strlen(name);
// Print upper part of the heart shape with stars
for(i=n/2; i<=n; i+=2){
for(j=1; j<n-i; j+=2){
printf(" ");
}
for(j=1; j<=i; j++){
printf("*");
}
for(j=1; j<=n-i; j++){
printf(" ");
}
for(j=1; j<=i; j++){
printf("*");
}
printf("
");
}
// Prints lower triangular part with stars
for(i=n; i>=1; i--){
for(j=i; j<n; j++){
printf(" ");
}
// Print the name on screen
if(i == n){
for(j=1; j<=(n * 2-len)/2; j++){
printf("*");
}
printf("%s", name);
for(j=1; j<(n*2-len)/2; j++){
printf("*");
}
}else{
for(j=1; j<=(i*2)-1; j++){
printf("*");
}
}
printf("
");
}
return 0;
}Output
When the above program is executed, it produces the following output −
Enter your name: Tutorials POint Enter no of rows: 10 ***** ***** ******* ******* ********* ********* **Tutorials POint* ***************** *************** ************* *********** ********* ******* ***** *** *
Updated on: 26-Mar-2021
2K+ Views
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