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C program to compare the structure variables
In C programming language, a structure is a collection of different datatype variables, which are grouped together under a single name.
Declaration and initialization of structures
The general form of a structure declaration is as follows −
datatype member1;
struct tagname{
datatype member2;
datatype member n;
};Here,
- struct is a keyword.
- tagname specifies the name of structure.
- member1, member2 specifies the data items that make up structure.
For example,
struct book{
int pages;
char author [30];
float price;
};Structure variables
There are three methods of declaring structure variables, which are as follows −
First method
struct book{
int pages;
char author[30];
float price;
}b;Second method
struct{
int pages;
char author[30];
float price;
}b;Third method
struct book{
int pages;
char author[30];
float price;
};
struct book b;Initialization and accessing of structures
The link between a member and a structure variable is established by using a member operator (or) a dot operator.
Initialization can be done in the following methods −
First method
struct book{
int pages;
char author[30];
float price;
} b = {100, “balu”, 325.75};Second method
struct book{
int pages;
char author[30];
float price;
};
struct book b = {100, “balu”, 325.75};Third method by using a member operator
struct book{
int pages;
char author[30];
float price;
} ;
struct book b;
b. pages = 100;
strcpy (b.author, “balu”);
b.price = 325.75;Example
Following is the C program for the comparison of structure variables −
struct class{
int number;
char name[20];
float marks;
};
main(){
int x;
struct class student1 = {001,"Hari",172.50};
struct class student2 = {002,"Bobby", 167.00};
struct class student3;
student3 = student2;
x = ((student3.number == student2.number) &&
(student3.marks == student2.marks)) ? 1 : 0;
if(x == 1){
printf("
student2 and student3 are same
");
printf("%d %s %f
", student3.number,
student3.name,
student3.marks);
}
else
printf("
student2 and student3 are different
");
}Output
When the above program is executed, it produces the following output −
student2 and student3 are same 2 Bobby 167.000000
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