# C Program to check if a number is divisible by sum of its digits

Given a number n we have to check whether the sum of its digits divide the number n or not. To find out we have to sum all the numbers starting from the unit place and then divide the number with the final sum.

Like we have a number “521” so we have to find the sum of its digit that will be “5 + 2 + 1 = 8” but 521 is not divisible by 8 without leaving any remainder.

Let’s take another example “60” where “6+0 = 6” which can divide 60 and will not leave any remainder.

## Example

Input: 55
Output: No
Explanation: 5+5 = 10; 55 not divisible by 10
Input: 12
Output: Yes
Explanation: 1+2 = 3; 12 is divisible by 3

The approach used below is as follows

To solve this problem we have to fetch each digit from the input and find the sum of each digit of a number, then check whether it is dividing the number or not.

• Take input
• Take each number from the unit place using and add it to a sum variable which should be initially zero
• Divide the input with the sum of the number.
• Return the result.

## Algorithm

In function int isDivisible(long int num)
Step 1-> Declare and initialize temp = num, sum = 0
Step 2-> Loop While num
Declare and initialize k as num % 10
Set sum as sum + k
Set num as num / 10
End Loop
Step 3-> If temp % sum == 0 then,
Return 1
Step 4-> Return 0
End function
In main()
Step 1-> Declare and initialize num as 55
Step 2-> If isDivisible(num) then,
Print "yes "
Step 3-> Else
Print "no "

## Example

Live Demo

#include <stdio.h>
// This function will check
// whether the given number is divisible
// by sum of its digits
int isDivisible(long int num) {
long int temp = num;
// Find sum of digits
int sum = 0;
while (num) {
int k = num % 10;
sum = sum + k;
num = num / 10;
}
// check if sum of digits divides num
if (temp % sum == 0)
return 1;
return 0;
}
int main() {
long int num = 55;
if(isDivisible(num))
printf("yes");
else
printf("no");
return 0;
}

## Output

If run the above code it will generate the following output −

No

Updated on: 21-Oct-2019

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