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C program to check if a given string is Keyword or not?
Keyword is a predefined or reserved word which is available in C++ library with a fixed meaning and used to perform an internal operation. C++ Language supports more than 64 keywords.
Every Keyword exists in lower case letters like auto, break, case, const, continue, int etc.
32 Keywords in C++ Language which is also available in the C language.
| auto | double | int | struct |
| break | else | long | switch |
| case | enum | register | typedef |
| char | extern | return | union |
| const | float | short | unsigned |
| continue | for | signed | void |
| default | goto | sizeof | volatile |
| do | if | static | while |
These are 30 reserved words that were not in C, but added to C++
| asm | dynamic_cast | namespace | reinterpret_cast |
| bool | explicit | new | static_cast |
| catch | false | operator | template |
| class | friend | private | this |
| const_cast | inline | public | throw |
| delete | mutable | protected | true |
| try | typeid | typename | using |
| using | using | wchar_t |
Input: str=”for” Output: for is a keyword
Explanation
Keywords are reserved words which cannot be used as variable names in program.
There are 32 keywords in the C programming language.
Compare the string with each keyword if the string is same then string is keyword
Example
#include <stdio.h>
#include <string.h>
int main() {
char keyword[32][10]={
"auto","double","int","struct","break","else","long",
"switch","case","enum","register","typedef","char",
"extern","return","union","const","float","short",
"unsigned","continue","for","signed","void","default",
"goto","sizeof","voltile","do","if","static","while"
} ;
char str[]="which";
int flag=0,i;
for(i = 0; i < 32; i++) {
if(strcmp(str,keyword[i])==0) {
flag=1;
}
}
if(flag==1)
printf("%s is a keyword",str);
else
printf("%s is not a keyword",str);
}Output
which is a keyword
Updated on: 07-Oct-2019
9K+ Views
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