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C program to add all perfect square elements in an array.
Problem
Write a program to find the sum of perfect square elements in an array.
Given a number of elements in array as input and the sum of all the perfect square of those elements present in the array is output.
Solution
For example,
Input= 1, 2, 3, 4, 5, 9,10,11,16 The perfect squares are 1, 4, 9, 16. Sum = 1 + 4 + 9 +16 = 30 Output: 30
Algorithm
Refer an algorithm given below to add the perfect square elements in an array.
Step 1 − Read number of elements in array at runtime.
Step 2 − Input the elements.
Step 3 − Declare and initialize the sum=0
Step 4 − Check, whether the array element is a perfect square or not.
Step 5 − If it is a perfect square, then, compute sum=sum+number.
Step 6 − Return sum.
Example
Following is the C program to find the sum of perfect square elements in an array −
#include<stdio.h>
#include<math.h>
int isPerfectSquare(int number){
int iVar;
float fVar;
fVar=sqrt((double)number);
iVar=fVar;
if(iVar==fVar)
return number;
else
return 0;
}
int main(){
int n;
printf("enter no: of elements:");
scanf("%d",&n);
int arr[n];
int i;
printf("enter the elements in an array:
");
for(i = 0; i < n; i++){
scanf("%d",&arr[i]);
}
int sum = 0;
for(i = 0; i < n; i++){
sum = sum + isPerfectSquare(arr[i]);
}
printf("sum=%d",sum);
return 0;
}Output
When the above program is executed, it produces the following output −
Run 1: enter no: of elements:5 enter the elements in an array: 1 3 5 9 10 sum=10 Run 2: enter no: of elements:5 enter the elements in an array: 1 4 9 16 25 sum=55
Updated on: 26-Mar-2021
2K+ Views
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