# C Program for sparse matrix

CServer Side ProgrammingProgramming

In a given matrix, when most of the elements are zero then, we call it as sparse matrix. Example − 3 x3 matrix

1 1 0
0 0 2
0 0 0

In this matrix, most of the elements are zero, so it is sparse matrix.

## Problem

Check whether a matrix is a sparse matrix or not.

## Solution

• Let us assume ZERO in the matrix is greater than (row * column)/2.

• Then, the matrix is a sparse matrix otherwise not.

## Program

Following is the program to check whether the given matrix is sparse matrix or not −

Live Demo

#include<stdio.h>
#include<stdlib.h>
int main(){
int row,col,i,j,a[10][10],count = 0;
printf("Enter row\n");
scanf("%d",&row);
printf("Enter Column\n");
scanf("%d",&col);
printf("Enter Element of Matrix1\n");
for(i = 0; i < row; i++){
for(j = 0; j < col; j++){
scanf("%d",&a[i][j]);
}
}
printf("Elements are:\n");
for(i = 0; i < row; i++){
for(j = 0; j < col; j++){
printf("%d\t",a[i][j]);
}
printf("\n");
}
/*checking sparse of matrix*/
for(i = 0; i < row; i++){
for(j = 0; j < col; j++){
if(a[i][j] == 0)
count++;
}
}
if(count > ((row * col)/2))
printf("Matrix is a sparse matrix \n");
else
printf("Matrix is not sparse matrix\n");
}

## Output

When the above program is executed, it produces the following result −

Run 1:
Enter row
3
Enter Column
2
Enter Element of Matrix1
1 0 2 0 2 0
Elements are:
1 0
2 0
2 0
Matrix is not sparse matrix
Run 2:
Enter row
3
Enter Column
2
Enter Element of Matrix1
1 0 0 0 0 0
Elements are:
1 0
0 0
0 0
Matrix is a sparse matrix
Published on 12-Mar-2021 06:38:55