# C Program Coin Change

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In this problem, we are given a value n, and we want to make change of n rupees, and we have n number of coins each of value ranging from 1 to m. And we have to return the total number of ways in which make the sum.

## Example

Input : N = 6 ; coins = {1,2,4}.
Output : 6
Explanation : The total combination that make the sum of 6
is :
{1,1,1,1,1,1} ; {1,1,1,1,2}; {1,1,2,2}; {1,1,4}; {2,2,2} ; {2,4}.

## Example

#include <stdio.h>
int coins( int S[], int m, int n ) {
int i, j, x, y;
int table[n+1][m];
for (i=0; i<m; i++)
table[0][i] = 1;
for (i = 1; i < n+1; i++) {
for (j = 0; j < m; j++) {
x = (i-S[j] >= 0)? table[i - S[j]][j]: 0;
y = (j >= 1)? table[i][j-1]: 0;
table[i][j] = x + y;
}
}
return table[n][m-1];
}
int main() {
int arr[] = {1, 2, 3};
int m = sizeof(arr)/sizeof(arr[0]);
int n = 4;
printf("The total number of combinations of coins that sum up to %d",n);
printf(" is %d ", coins(arr, m, n));
return 0;
}

## Output

The total number of combinations of coins that sum up to 4 is 4
Updated on 22-Nov-2019 09:28:52