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ByteBuffer compareTo() method in Java
A buffer can be compared with another buffer using the method compareTo() in the class java.nio.ByteBuffer. This method returns a negative integer if the buffer is less than the given buffer, zero if the buffer is equal to the given buffer and a positive integer if the buffer is greater than the given buffer.
A program that demonstrates this is given as follows −
Example
import java.nio.*; import java.util.*; public class Demo { public static void main(String[] args) { int n = 5; try { ByteBuffer buffer1 = ByteBuffer.allocate(n); buffer1.put((byte)1); buffer1.put((byte)2); buffer1.put((byte)3); buffer1.put((byte)4); buffer1.put((byte)5); buffer1.rewind(); System.out.println("The first ByteBuffer is: " + Arrays.toString(buffer1.array())); ByteBuffer buffer2 = ByteBuffer.allocate(n); buffer2.put((byte)1); buffer2.put((byte)2); buffer2.put((byte)3); buffer2.put((byte)4); buffer2.put((byte)5); buffer2.rewind(); System.out.println("The second ByteBuffer is: " + Arrays.toString(buffer2.array())); int val = buffer1.compareTo(buffer2); if (val == 0) System.out.println("
Both the buffers are lexicographically equal"); else if (val > 0) System.out.println("
The first buffer is lexicographically greater than the second buffer"); else System.out.println("
The second buffer is lexicographically greater than the first buffer"); } catch (IllegalArgumentException e) { System.out.println("Error!!! IllegalArgumentException"); } catch (ReadOnlyBufferException e) { System.out.println("Error!!! ReadOnlyBufferException"); } } }
Output
The first ByteBuffer is: [1, 2, 3, 4, 5] The second ByteBuffer is: [1, 2, 3, 4, 5] Both the buffers are lexicographically equal
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