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Average of first n odd naturals numbers?
Here we will see how to get the average of n odd natural numbers. The n is given by the user. To get the ith odd number we can use this formula 2*i+1. Here also we are using this formula. Let us see the algorithm to get the clear idea.
Algorithm
avgOddNaturalNumber(n)
Begin sum := 0 for i in range 0 to n-1, do sum := sum + (2i + 1) done return sum/n End
Example
#include<iostream>
using namespace std;
float asciiAverage(string str){
int sum = 0;
for(int i = 0; i<str.size(); i++){
sum += int(str[i]);
}
return sum/str.size();
}
main() {
string str;
cout << "Enter a string: ";
cin >> str;
cout << "ASCII average is: " << asciiAverage(str);
}Output
Enter a string: Hello ASCII average is: 100
Updated on: 30-Jul-2019
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