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Average of first n even natural numbers?
Average or mean of n even natural number is the sum of numbers divided by the numbers.
You can calculate this by two methods &minus
Find the sum of n even natural numbers and divide it by number, Using loop.
- Find the sum of n even natural numbers and divide it by number, Using formula.
Method 1 - Using Loop
Find the sum of even natural numbers using a loop that counts up to the number we want the sum. Then we will divide it by n.
Example Code
#include <stdio.h>
int main(void) {
int n = 5;
int sum = 0;
int average = 0;
for (int i = 1; i <= n ; i++) {
sum += (i*2);
}
average = sum / n;
printf("The average of %d even natural numbers is %d", n,average);
return 0;
}Output
The average of 5 even natural numbers is 6
Method 1 − Using Formula
Find the sum of even natural numbers using a mathematical Formula that directly calculates the average.
The formula is (n + 1) = n*(n + 1 )/ n..
Example Code
#include <stdio.h>
int main(void) {
int n = 5;
int average = n+1 ;
printf("The average of %d even natural numbers is %d", n,average);
return 0;
}Output
The average of 5 even natural numbers is 6
The second method that uses formula is better because in cases with larger value of n, the loop will run n time will increase the time.
Updated on: 30-Jul-2019
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