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# Average of first n even natural numbers?

Average or mean of n even natural number is the sum of numbers divided by the numbers.

You can calculate this by two methods &minus

Find the sum of n even natural numbers and divide it by number, Using loop.

- Find the sum of n even natural numbers and divide it by number, Using formula.

## Method 1 - Using Loop

Find the sum of even natural numbers using a loop that counts up to the number we want the sum. Then we will divide it by n.

## Example Code

#include <stdio.h> int main(void) { int n = 5; int sum = 0; int average = 0; for (int i = 1; i <= n ; i++) { sum += (i*2); } average = sum / n; printf("The average of %d even natural numbers is %d", n,average); return 0; }

## Output

The average of 5 even natural numbers is 6

## Method 1 − Using Formula

Find the sum of even natural numbers using a mathematical Formula that directly calculates the average.

The formula is (n + 1) = n*(n + 1 )/ n..

## Example Code

#include <stdio.h> int main(void) { int n = 5; int average = n+1 ; printf("The average of %d even natural numbers is %d", n,average); return 0; }

## Output

The average of 5 even natural numbers is 6

The second method that uses formula is better because in cases with larger value of n, the loop will run n time will increase the time.

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