Arnab Chakraborty

Arnab Chakraborty

29 Articles Published

Articles by Arnab Chakraborty

Page 3 of 3

Java regex to exclude a specific String constant

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Sep-2024 2K+ Views

In this program, we will use a regular expression to check if a given string does not contain the substring "kk" using Java. The regular expression ^((?!kk).)*$ is designed to match strings that do not include the "kk" pattern anywhere in the string. The program will evaluate a sample string and print whether or not it contains "kk". Problem Statement Write a program in Java for checking whether a given string contains the substring "kk." If the string does not contain "kk" the program will return true otherwise it will return false. Input String s = "tutorials" Output true ...

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How to test if a Java String contains a case insensitive regex pattern

Arnab Chakraborty
Arnab Chakraborty
Updated on 24-Jun-2020 477 Views

the syntax? i:x makes the string search case-insensitive. for egpublic class RegCaseSense {    public static void main(String[] args) {       String stringSearch = "HI we are at java class.";       // this won't work because the pattern is in upper-case       System.out.println("Try this 1: " + stringSearch.matches(".*CLASS.*"));         // the magic (?i:X) syntax makes this search case-insensitive, so it returns true       System.out.println("Try this 2: " + stringSearch.matches("(?i:.*CLASS.*)"));    } }

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Match all occurrences of a regex in Java

Arnab Chakraborty
Arnab Chakraborty
Updated on 23-Jun-2020 321 Views

public class RegexOccur {    public static void main(String args[]) {       String str = "java is fun so learn java";       String findStr = "java";       int lastIndex = 0;       int count = 0;       while(lastIndex != -1) {          lastIndex = str.indexOf(findStr,lastIndex);          if(lastIndex != -1) {             count ++;             lastIndex += findStr.length();          }       }       System.out.println(count);    } }Output2

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How do I use jQuery effects?

Arnab Chakraborty
Arnab Chakraborty
Updated on 22-Jun-2020 273 Views

For hiding and showing the div, you can use hide and show method.For hiding$('#id1').hide();For showing$('#id1').show();Example showhide                 $(document).ready(function () {          $('#btn1').click(function () {             $('#id1').hide();          });          $('#btn2').click(function () {             $('#id1').show();          });       });        I Am A Simple Paragraph    Hide    Show MethodDescriptionanimate()Runs a custom animation on the selected elementsclearQueue()Removes all remaining queued functions ...

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Why we should use whole string in Java regular expression

Arnab Chakraborty
Arnab Chakraborty
Updated on 21-Jun-2020 1K+ Views

In Java regex matches() matches the input string against the whole string as it add a ^ and $ at the end of the input string.so it will not match the substring. So for matching substring, you should use find().Exampleimport java.util.regex.*; class PatternMatchingExample {    public static void main(String args[]) {       String content = "aabbcc";       String string = "aa";       Pattern p = Pattern.compile(string);       Matcher m = p.matcher(content);       System.out.println(" 'aa' Match:"+ m.matches());       System.out.println(" 'aa' Match:"+ m.find());    } }Output'aa' Match:false 'aa' Match:true

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How to extract a group from a Java String that contains a Regex pattern

Arnab Chakraborty
Arnab Chakraborty
Updated on 21-Jun-2020 386 Views

How to extract a group from a Java String that contains a Regex patternimport java.util.regex.Matcher; import java.util.regex.Pattern; public class RegexTest {    public static void main(String[] args) {       Pattern pattern = Pattern.compile("fun");       Matcher matcher = pattern.matcher("Java is fun");       // using Matcher find(), group(), start() and end() methods       while (matcher.find()) {          System.out.println("Found the text "" + matcher.group()             + "" starting at " + matcher.start()             + " index and ending at index ...

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How to capture multiple matches in the same line in Java regex

Arnab Chakraborty
Arnab Chakraborty
Updated on 20-Jun-2020 3K+ Views

Exampleimport java.util.regex.*; class PatternMatcher {    public static void main(String args[]) {       int count = 0;       // String to be scanned to find the pattern.       String content = "aaa bb aaa";       String string = "aaa";       // Create a Pattern object       Pattern p = Pattern.compile(string);       // get a matcher object       Matcher m = p.matcher(content);       while(m.find()) {          count++;          System.out.println("Match no:"+count);         ...

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Java Regular Expression that doesn't contain a certain String.

Arnab Chakraborty
Arnab Chakraborty
Updated on 20-Jun-2020 726 Views

Exampleimport java.util.regex.*; class PatternMatch{    public static void main(String args[]) {       String content = "I am a student";       String string = ".*boy.*";       boolean isMatch = Pattern.matches(string, content);       System.out.println("The line contains 'boy'?"+ isMatch);    } }Outputthe line contains 'boy'?falsematches()­­It is used to check if the whole text matches a pattern. Its output is boolean. It returns true if match is found otherwise false.This is one of simplest and easiest way of searching a String in a text using Regex .There is a another method compile() , if you want ...

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How to use R in Java-8 regex.

Arnab Chakraborty
Arnab Chakraborty
Updated on 30-Jul-2019 554 Views

\R matches any line break as defined by the Unicode standardPattern p = Pattern.compile("\R");Unicode line-break sequence is equivalent to \u000D\u000A|[\u000A\u000B\u000C\u000D\u0085\u2028\u2029]

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