Programming Articles

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C++ program to find the smallest element among three elements

Ayush Gupta
Ayush Gupta
Updated on 09-Jul-2020 2K+ Views

In this tutorial, we will be discussing a program to find the smallest element among the provided three elements.We will be provided with three elements/ integers and our task is to compare them and find the smallest element/ integer among them.Example#include using namespace std; int main() {    int a = 45, b = 72, c = 10;    if (a

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C++ program to find the Sum of each Row and each Column of a Matrix

Ayush Gupta
Ayush Gupta
Updated on 09-Jul-2020 3K+ Views

In this tutorial, we will be discussing a program to find the sum of each row and each column for a given matrix.For this, we will be given with a say A*B matrix. Our task is to traverse through all the elements of the matrix and find the sum of each row and each column of the matrix.Example#include using namespace std; #define m 7 #define n 6 //calculating sum of each row void calc_rsum(int arr[m][n]){    int i,j,sum = 0;    for (i = 0; i < 4; ++i) {       for (j = 0; j < 4; ++j) {          sum = sum + arr[i][j];       }       cout

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C++ program to find the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n)

Ayush Gupta
Ayush Gupta
Updated on 09-Jul-2020 421 Views

In this tutorial, we will be discussing a program to find the sum of the given series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n).For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.Example#include using namespace std; //calculating the sum of the series int calc_sum(int n) {    int i;    int sum = 0;    for (i = 1; i

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C++ program to find the sum of the series (1/a + 2/a^2 + 3/a^3 + ... + n/a^n)

Ayush Gupta
Ayush Gupta
Updated on 09-Jul-2020 188 Views

In this tutorial, we will be discussing a program to find the sum of the given series (1/a + 2/a^2 + 3/a^3 + … + n/a^n).For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.Example#include #include using namespace std; //calculating the sum of the series float calc_sum(int a, int n) {    int i;    float sum = 0;    for (i = 1; i

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C++ Program to find the sum of the series 23+ 45+ 75+..... upto N terms

Ayush Gupta
Ayush Gupta
Updated on 09-Jul-2020 281 Views

In this tutorial, we will be discussing a program to find the sum of the given series 23+ 45+ 75+….. upto N terms.For this, we will be given with the value of N and our task is to add up every term starting from the first one to find the sum of the given series.After solving this, we get the formula for the sum of the series;Sn = (2n(n+1)(4n+17)+54n)/6Example#include using namespace std; //calculating the sum of the series int calc_sum(int N) {    int i;    int sum = (2 * N * (N + 1) * (4 * ...

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C++ program to find the sum of the series 1 + 1/2^2 + 1/3^3 + .....+ 1/n^n

Ayush Gupta
Ayush Gupta
Updated on 09-Jul-2020 872 Views

In this tutorial, we will be discussing a program to find the sum of the given series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n.For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.Example#include #include using namespace std; //calculating the sum of the series double calc_sum(int n) {    int i;    double sum = 0.0, ser;    for (i = 1; i

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C++ Program for Deadlock free condition in Operating Systems

Sunidhi Bansal
Sunidhi Bansal
Updated on 09-Jul-2020 4K+ Views

Given with the P number of processes in the memory and N number of needed resources by them to complete their execution and the task is to find the minimum number of resources R which should be allotted to the processes such that deadlock will never occur.What is a DeadlockDeadlock is situation in an operating system where multiple processes residing in the memory doesn’t able to perform their execution because the resources which are needed for program execution is being hold by another resource who is waiting for some other resource for completion.Let’s say there are two processes P1 and ...

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C++ Program for class interval arithmetic mean

Sunidhi Bansal
Sunidhi Bansal
Updated on 09-Jul-2020 769 Views

We are given with three arrays where first array contains the upper limit for arithmetic mean, second array contains the lower limit for arithmetic mean and third array contains the frequencies and the task is to generate the arithmetic mean of class intervals given.What is Arithmetic Mean?Arithmetic mean is the average value that is calculated by dividing the sum of all the elements in the set with the total number of elements in the given set.How to calculate Class Interval Arithmetic MeanGiven with Lower Limit, Upper Limit, FrequencyLower LimitUpper LimitFrequency121342563784Calculate the mid-point by adding the upper limit and lower limit ...

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C++ Program for triangular pattern (mirror image around 0)

Sunidhi Bansal
Sunidhi Bansal
Updated on 09-Jul-2020 404 Views

Given with the positive value n and the task is to generate the triangular pattern i.e. mirror image of the printed numbers and display the resultExampleInput-: n = 6 Output-:Input-: n = 3 Output-:Approach used in the below program is as follows −Input the value of n as a positive integerTraverse one loop i for the number of rows in a pattern i.e. nTraverse one loop j for the number of spaces in a patternTraverse another loop for the digits in a patternAlgorithmSTART Step 1-> declare function to print mirror image of triangular pattern    void print_mirror(int n)    declare ...

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C++ program for Find sum of odd factors of a number

Sunidhi Bansal
Sunidhi Bansal
Updated on 09-Jul-2020 649 Views

Given with a positive integer and the task is to generate the odd factors of a number and finding out the sum of given odd factors.ExampleInput-: number = 20 Output-: sum of odd factors is: 6 Input-: number = 18 Output-: sum of odd factors is: 13So, result = 1 + 5 = 6Approach used in the below program is as follows −Input the number for calculating the sum of odd factors of that numberIgnore the digit 0 and 2 because both are even digits and store the digit 1 because it is an odd digitStart the loop from 3 ...

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