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Programming Articles
Page 2309 of 2547
Differences between anonymous class and lambda expression in Java?
Anonymous class is an inner class without a name, which means that we can declare and instantiate class at the same time. A lambda expression is a short form for writing an anonymous class. By using a lambda expression, we can declare methods without any name.Anonymous class vs Lambda ExpressionAn anonymous class object generates a separate class file after compilation that increases the size of a jar file while a lambda expression is converted into a private method. It uses invokedynamic bytecode instruction to bind this method dynamically, which saves time and memory.We use this keyword to represent the current ...
Read MoreHow to implement lambda expression without creating an anonymous class in Java?
A lambda expression is an anonymous function without having any name and does not belong to any class that means it is a block of code that can be passed around to execute.Syntax(parameter-list) -> {body}We can implement a lambda expression without creating an anonymous inner class in the below program. For the button's ActionListener interface, we need to override one abstract method addActionListener() and implement the block of code using the lambda expression.Exampleimport java.awt.*; import java.awt.event.*; import javax.swing.*; public class LambdaExpressionButtonTest extends JFrame { private JButton btn; public LambdaExpressionButtonTest() { ...
Read MoreAre lambda expressions objects in Java?
Yes, any lambda expression is an object in Java. It is an instance of a functional interface. We have assigned a lambda expression to any variable and pass it like any other object.Syntax(parameters) -> expression or (parameters) -> { statements; }In the below example, how a lambda expression has assigned to a variable and how it can be invoked.Example@FunctionalInterface interface ComparatorTask { public boolean compare(int t1, int t2); } public class LambdaObjectTest { public static void main(String[] args) { ...
Read MoreWhat are the scoping rules for lambda expressions in Java?
There are different scoping rules for lambda expression in Java. In lambda expressions, this and super keywords are lexically scoped means that this keyword refers to the object of the enclosing type and the super keyword refers to the enclosing superclass. In the case of an anonymous class, they are relative to the anonymous class itself. Similarly, local variables declared in lambda expression conflicts with variables declared in the enclosing class. In the case of an anonymous class, they are allowed to shadow variables in the enclosing class.Example@FunctionalInterface interface TestInterface { int calculate(int x, int y); } ...
Read MoreHow many parameters can a lambda expression have in Java?
The lambda expressions are easy and contain three parts like parameters (method arguments), arrow operator (->) and expressions (method body). The lambda expressions can be categorized into three types: no parameter lambda expressions, single parameter lambda expressions and multiple parameters lambda expressions.Lambda Expression with no parameterWe need to create no parameter lambda expression then start the expression with empty parenthesis.Syntax() -> { //Body of no parameter lambda }Example(no parameter Lambda)import java.util.function.*; import java.util.Random; public class LambdaExpression1 { public static void main(String args[]) { NumberUtil num = new ...
Read MoreWhat are block lambda expressions in Java?
A lambda block states that lambda expression with multiple statements. It expands the type of operations to perform with a lambda expression. The multiple statements containing bodies are called expression bodies. A lambda expression with expression bodies is called expression lambdas. Whenever we are using expression lambdas, explicitly use a return statement to return a value.Exampleinterface NumberFinder { int finder(int number1, int number2); } public class LambdaNumberFinder { public static void main(String args[]) { NumberFinder numberFinder = (number1, number2) -> { ...
Read MoreC++ program to implement Run Length Encoding using Linked Lists
In this tutorial, we will be discussing a program to implement Run Length Encoding using Linked Lists.For this we will be given with a linked list. OUr task is too encode the elements of the Linked List using Run Length Encoding.For example, if the elements of the linked list are “a->a->a->a->a” then in run length encoding they will be replaced by “a → 5”.Example#include using namespace std; //structuring linked list node struct Node { char data; struct Node* next; }; //creating a new node Node* newNode(char data){ Node* temp = new Node; temp->data = data; ...
Read MoreBinary representation of previous number in C++
In this problem, we are given the binary representation of a number and we have to find the binary representation of the previous number i.e. the number that is resulted after subtracting one from the given number.Binary representation of a number is changing the base of the number to base 2 and representing the number using only 0 or 1.For example, Binary representation of 23 is 10111.So, here we would be given a number, let's say n in binary form. And we have to find the binary representation of n-1.To solve this problem, we need to know the basics of ...
Read MoreC++ program to find the rate percentage from compound interest of consecutive years
In this tutorial, we will be discussing a program to find the rate percentage from compound interest of the consecutive years.For this, we will be provided with two integers say A and B that are the interests of two consecutive years. Our task is to find the rate of interest for the given values.Finding the relation between the given values and eliminating the principal amount, we get the formula asrate = ((B-A)*100)/AExample#include using namespace std; //calculating the rate of interest float calc_rate(int N1, int N2) { float rate = (N2 - N1) * 100 / float(N1); return ...
Read MoreC++ program to find the side of the Octagon inscribed within the square
In this tutorial, we will be discussing a program to find the side of the octagon inscribed within a given square.For this, we will be given with the side of a square and our task is to find the side of the largest octagon that can be inscribed in it.Finding the relation between the sides of the square and the octagon, we find the formula for the side of the octagonside of square/(√2 + 1)Example#include using namespace std; //calculating the side of the octagon float calc_oside(float a) { if (a < 0) return -1; ...
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