Shuffle Array Contents

George John

Answered on 12th Jul, 2018, 2 Views

This algorithm will take an array and shuffle the contents of the array. It will generate a random permutation of the array elements.

To solve this problem, we will swap elements starting from the last index to randomly generated an index in the array.

Input and Output

Input: 
An array of integers: {1, 2, 3, 4, 5, 6, 7, 8}
Output: 
Shuffle of array contents: 3 4 7 2 6 1 5 8 (Output may differ for next run)

Algorithm

randomArr(array, n)

Input: The array, number of elements.

Output: Shuffle the contents of the array.

Begin
   for i := n – 1 down to 1, do
      j := random number from 0 to i
      swap arr[i] and arr[j]
   done
End

Source Code (C++)

#include <iostream>
#include<cstdlib>
#include <ctime>
using namespace std;

void display(int array[], int n) {
   for (int i = 0; i < n; i++)
      cout << array[i] << " ";
}

void randomArr ( int arr[], int n ) {           //generate random array element
   srand (time(NULL));                 //use time to get different seed value to start
   for (int i = n-1; i > 0; i--) {
      int j = rand() % (i+1);           //randomly choose an index from 0 to i
      swap(arr[i], arr[j]);            //swap current element with element placed in jth location
   }
}

int main() {
   int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
   int n = 8;
   randomArr(arr, n);
   display(arr, n);
}

Output

4 7 8 2 6 3 5 1