Peak Element in 2D array

Divide and Conquer AlgorithmsData StructureAlgorithms

An item is said to be a peak element when it is greater than or equal with all four neighbor of that element. The neighbor elements are the top, bottom, left and right elements. For this problem, we will consider some bounds. The diagonal elements are not checked as neighbor elements. More than one peak element may present in a matrix, and the peak element is not necessarily the largest element in the matrix.

Input and Output

A matrix of different numbers.
10  8  10  10
14 13  12  11
15  9  11  11
15  9  11  21
16 17  19  20

The peak element of the matrix.
Here the peak element is: 21


findMaxMid(rows, mid, max)

Input: Rows number of the matrix, mid row, a max element as an output argument.

Output: Update the max item and index of the max element.

   maxIndex := 0
   for all rows r in the matrix, do
      if max < matrix[i, mid], then
         max = matrix[i, mid],
         maxIndex := r
   return maxIndex

findPeakElement(rows, columns, mid)

Input − Row and column of the matrix, and mid row place.

Output − Peak element in the matrix.

   maxMid := 0
   maxMidIndex := findMaxMid(rows, mid, maxMid)

   if mid is first or last column, then
      return maxMid

   if maxMid>= item of previous and next row for mid column, then
      return maxMid

   if maxMid is less than its left element, then
      res := findPeakElement(rows, columns, mid – mid/2)
      return res

   if maxMid is less than its right element, then
      res := findPeakElement(rows, columns, mid + mid/2)
      return res


#define M 4
#define N 4
using namespace std;

intarr[M][N] = {
   {10, 8, 10, 10},
   {14, 13, 12, 11},
   {15, 9, 11, 21},
   {16, 17, 19, 20}

intfindMaxMid(int rows, int mid, int&max) {
   intmaxIndex = 0;

   for (int i = 0; i < rows; i++) {    //find max element in the mid column
      if (max <arr[i][mid]) {
         max = arr[i][mid];
         maxIndex = i;
   return maxIndex;

intfindPeakElement(int rows, int columns, int mid) {
   intmaxMid = 0;
   intmaxMidIndex = findMaxMid(rows, mid, maxMid);

   if (mid == 0 || mid == columns-1)    //for first and last column, the maxMid is maximum
      return maxMid;
   // If maxMid is also peak
   if (maxMid>= arr[maxMidIndex][mid-1] &&maxMid>= arr[maxMidIndex][mid+1])
      return maxMid;

   if (maxMid<arr[maxMidIndex][mid-1])     // If maxMid is less than its left element
      return findPeakElement(rows, columns, mid - mid/2);
   return findPeakElement(rows, columns, mid+mid/2);

int main() {
   int row = 4, col = 4;
   cout<< "The peak element is: "<<findPeakElement(row, col, col/2);


The peak element is: 21
Updated on 16-Jun-2020 09:33:16