Overloading unary operator in C++?

The operator keyword declares a function specifying what operator-symbol means when applied to instances of a class. This gives the operator more than one meaning, or "overloads" it. The compiler distinguishes between the different meanings of an operator by examining the types of its operands.

The unary operators operate on a single operand and following are the examples of Unary operators −

• The increment (++) and decrement (--) operators.
• The unary minus (-) operator.
• The logical not (!) operator.

The unary operators operate on the object for which they were called and normally, this operator appears on the left side of the object, as in !obj, -obj, and ++obj but sometime they can be used as postfix as well like obj++ or obj--.

Following example explain how bang(!) operator can be overloaded for prefix usage −

Example

#include <iostream>
using namespace std;

class Distance {
   private:
   int feet; // 0 to infinite
   int inches; // 0 to 12

   public:
   // Constructor
   Distance(int f, int i) {
      feet = f;
      inches = i;
   }

   // method to display distance
   void display() {
      cout << "F: " << feet << " I:" << inches <<endl;
   }

   // overloaded bang(!) operator
   Distance operator!() {
      feet = -feet;
      inches = -inches;
      return Distance(feet, inches);
   }
};
int main() {
   Distance D1(3, 4), D2(-1, 10);

   !D1;
   D1.display();   // display D1

   !D2;            // apply negation
   D2.display();   // display D2

   return 0;
}

Output

This will give the output −

F: -3 I:-4
F: 1 I:-10

Ankitha Reddy

Published on 15-Feb-2018 22:42:17