Java program to print the reverse of the given number

Following is the algorithm to reverse a given number.


1. Get the number to reverse.
2. Hold the number in temporary variable.
3. Start the while loop with condition temp >0.
4. Store the first digit in the temporary variable d by performing modulus
operation on temp with 10.
5. Multiply the revnum (initialized with 0) with 10 and concatenate the digit
obtained in the previous step.
6. Reduce one digit in the temp by dividing with 10.


import java.util.Scanner;
public class ReverseOfANumber {
   public static void main(String args[]) {
      int d, number,temp, revnum = 0;
      Scanner sc = new Scanner(;
      System.out.println("Enter a number ::");
      number = sc.nextInt();
      temp = number;
      while (temp >0) {
         d = temp %10;
         revnum = (revnum*10)+d;
         temp = temp/10;
      System.out.println("Reverse of the given number is:"+revnum);


Enter a number ::
Reverse of the given number is:5112115

karthikeya Boyini
karthikeya Boyini

I love programming (: That's all I know

Updated on: 30-Jul-2019


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