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Static method in Interface in Java
To implement static method in Interface, the Java code is as follows −
Example
interface my_interface{
static void static_fun(){
System.out.println("In the newly created static method");
}
void method_override(String str);
}
public class Demo_interface implements my_interface{
public static void main(String[] args){
Demo_interface demo_inter = new Demo_interface();
my_interface.static_fun();
demo_inter.method_override("In the override method");
}
@Override
public void method_override(String str){
System.out.println(str);
}
}Output
In the newly created static method In the override method
An interface is defined, inside which a static function is defined. Another function named ‘method_override’ is defined without a body. This interface is implemented by another class named ‘Demo_interface’. Inside this class, the main function is defined, and an instance of this ‘Demo_interface’ is also created. The static function is called on this instance, and next, the ‘method_override’ function is called on this instance. An override specification is written, under which the ‘method_override’ is defined. This function just prints the string on the console.
Updated on: 13-Jul-2020
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