How to find the product of two binary numbers using C#?

To find the product of two binary numbers, firstly set them.

val1 = 11100;
val2 = 10001;

Console.WriteLine("Binary one: "+val1);
Console.WriteLine("Binary two: "+val2);

Now loop through to get the product.

while (val2 != 0) {
   digit = val2 % 10;
   if (digit == 1) {
      val1 = val1 * factor;
      prod = displayMul(val1, prod);
   } else
   val1 = val1 * factor;
   val2 = val2 / 10;
   factor = 10;
}
Console.WriteLine("Product = {0}", prod);

Above a method displayMul() is called with the first binary number.

static long displayMul (long val1, long val2) {
   long i = 0, rem = 0, mul = 0;
   long[] sum = new long[30];

   while (val1 != 0 || val2 != 0) {
      sum[i++] =(val1 % 10 + val2 % 10 + rem) % 2;
      rem =(val1 % 10 + val2 % 10 + rem) / 2;
      val1 = val1 / 10;
      val2 = val2 / 10;
   }
   if (rem != 0)
   sum[i++] = rem;
   i = i-1;;

   while (i >= 0)
   mul = mul * 10 + sum[i--];
   return mul;
}

Here is the complete code −

Example

 Live Demo

using System;
class Demo {
   public static void Main(string[] args) {
      long val1, val2, prod = 0;
      long digit, factor = 1;

      val1 = 11100;
      val2 = 10001;

      Console.WriteLine("Binary one: "+val1);
      Console.WriteLine("Binary two: "+val2);

      while (val2 != 0) {
         digit = val2 % 10;
         if (digit == 1) {
            val1 = val1 * factor;
            prod = displayMul(val1, prod);
         } else
         val1 = val1 * factor;
         val2 = val2 / 10;
         factor = 10;
      }
      Console.WriteLine("Product = {0}", prod);
   }

   static long displayMul (long val1, long val2) {
      long i = 0, rem = 0, mul = 0;
      long[] sum = new long[30];

      while (val1 != 0 || val2 != 0) {
         sum[i++] =(val1 % 10 + val2 % 10 + rem) % 2;
         rem =(val1 % 10 + val2 % 10 + rem) / 2;
         val1 = val1 / 10;
         val2 = val2 / 10;
      }
      if (rem != 0)
      sum[i++] = rem;
      i = i-1;;

      while (i >= 0)
      mul = mul * 10 + sum[i--];
      return mul;
   }
}

Output

Binary one: 11100
Binary two: 10001
Product = 111011100