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How to capture multiple matches in the same line in Java regex
Example
import java.util.regex.*; class PatternMatcher { public static void main(String args[]) { int count = 0; // String to be scanned to find the pattern. String content = "aaa bb aaa"; String string = "aaa"; // Create a Pattern object Pattern p = Pattern.compile(string); // get a matcher object Matcher m = p.matcher(content); while(m.find()) { count++; System.out.println("Match no:"+count); System.out.println("Found at: "+ m.start()+ " - " + m.end()); } } }
Output
Match no:1 Found at: 0 - 3 Match no:2 Found at: 7 - 10
Note
start() – This method used for getting the start index of a match that is being found using find() method.
end() –This method used for getting the end index of a match that is being found using find() method. It returns index of character next to last matching character.
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