Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
How can I use a SELECT statement as an argument of MySQL IF() function?
It is quite possible to use a SELECT statement as the first argument of MySQL IF() function. To make it understand, consider the data as follows from table ‘Students’.
mysql> Select * from Students; +----+-----------+-----------+----------+----------------+ | id | Name | Country | Language | Course | +----+-----------+-----------+----------+----------------+ | 1 | Francis | UK | English | Literature | | 2 | Rick | USA | English | History | | 3 | Correy | USA | English | Computers | | 4 | Shane | France | French | Computers | | 5 | Validimir | Russia | Russian | Computers | | 6 | Steve | Australia | English | Geoinformatics | | 7 | Rahul | India | Hindi | Yoga | | 8 | Harshit | India | Hindi | Computers | | 9 | Harry | NZ | English | Electronics | +----+-----------+-----------+----------+----------------+ 9 rows in set (0.00 sec)
Now the following query will use SELECT Statement within IF() function
mysql> Select ID, IF((Select COUNT(*) FROM Students WHERE Language = 'English')>(Select COUNT(*) from Students WHERE Language <> 'English'),(CONCAT("Name is ", Name)),(CONCAT("Course is ", Course))) AS 'Name/Course' from Students;
+----+-------------------+
| ID | Name/Course |
+----+-------------------+
| 1 | Name is Francis |
| 2 | Name is Rick |
| 3 | Name is Correy |
| 4 | Name is Shane |
| 5 | Name is Validimir |
| 6 | Name is Steve |
| 7 | Name is Rahul |
| 8 | Name is Harshit |
| 9 | Name is Harry |
+----+-------------------+
9 rows in set (0.00 sec)
Updated on: 30-Jul-2019
355 Views
Advertisements