Find LCM of two numbers

In mathematics Least Common Multiple (LCM) is the smallest possible integer, that is divisible by both numbers.

LCM can be calculated by many methods, like factorization, etc. but in this algorithm, we have multiplied the bigger number with 1, 2, 3…. n until we find a number which is divisible by the second number.

Input and Output

Input:
Two numbers: 6 and 9
Output:
The LCM is: 18

Algorithm

LCMofTwo(a, b)

Input: Two numbers a and b, considered a > b.

Output: LCM of a and b.

Begin
   lcm := a
   i := 2
   while lcm mod b ≠ 0, do
      lcm := a * i
      i := i + 1
   done

   return lcm
End

Example

#include<iostream>
using namespace std;

int findLCM(int a, int b) {    //assume a is greater than b
   int lcm = a, i = 2;

   while(lcm % b != 0) {    //try to find number which is multiple of b
      lcm = a*i;
      i++;
   }
   return lcm;    //the lcm of a and b
}

int lcmOfTwo(int a, int b) {
   int lcm;
   if(a>b)    //to send as first argument is greater than second
      lcm = findLCM(a,b);
   else
      lcm = findLCM(b,a);
   return lcm;
}

int main() {
   int a, b;
   cout << "Enter Two numbers to find LCM: "; cin >> a >> b;
   cout << "The LCM is: " << lcmOfTwo(a,b);
}

Output

Enter Two numbers to find LCM: 6 9
The LCM is: 18