8085 program to move blocks of bits from source location to a destination location

Microprocessor8085

Problem Statement − Move a block of 16 data stored from 8050H to 805FH to a target location from 8070F to 807FH.

Algorithm
Address Hex Codes Label Mnemonic T-States Comment
8000

21

50

80

START: LXI H, 8050H 10 Setup HL pair as a pointer for source memory.
8003

11

70

80

LXI D, 8070H 10 Set up DE pair as a pointer for destination memory
8006

06

10

MVI B, 10H 7 Set up B to count 16 bytes
8008 7E LOOP: MOV A, M 7 Get data byte from source.
8009 12 STAX D 7 Store data byte as destination
800A 23 INX H 6 Point HL to next source location
800B 13 INX D 6 Point DE to next destination
800C 05 DCR B 4 Decrement count
800D

C2

08

80

JNZ LOOP 10 If counter is not 0, go back to transfer next byte.
8010 76 HLT 5 Stop
Total 17 Bytes Total 69 T-States

Total T-States = TOutside_loop + TInside_loop

TOutside_loop = (10+10+7+5) = 32

TInside_loop = ((7+7+6+6+4+10) * 16 - 3) = (40 * 16 - 3) = 637

so Total T-States = 32 + 637 = 669

The Main program is started from location 8000H – 8010H.

Source Data Block from 8050H – 805FH.

Destination block from 8070H – 807FH

Input Output
Address Value Address Value
8050H 00 8070H 00
8051H 11 8071H 11
8052H 22 8072H 22
8053H 33 8073H 33
8054H 44 8074H 44
8055H 55 8075H 55
8056H 66 8076H 66
8057H 77 8077H 77
8058H 88 8078H 88
8059H 99 8079H 99
805AH AA 807AH AA
805BH BB 807BH BB
805CH CC 807CH CC
805DH DD 807DH DD
805EH EE 807EH EE
805FH FF 807FH FF
raja
Published on 05-Dec-2018 11:05:57
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