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Progression - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - Which term of the A.P. 2, 7, 12, 17...are 87?

Answer : C

Explanation

 Here a =2, d= (7-2) =5.
Let the nth term be 87. Then,
a + (n-1) d =87 ⇒ 2+ (n-1)*5 = 87
⇒ (n-1)*5= 85 ⇒ (n-1) = 17 ⇒ n = 18 ∴ 18th term is 87.

Q 2 - What number of numbers arrive somewhere around 10 and 200 which are precisely separable by 7?

Answer : D

Explanation

Requisite numbers are 14, 21, 28, 35 .., 196.
This is an A.P. in which a = 14 and d = 7
a +(n-1) d = 196 ⇒  14+(n-1)*7 =196
= (n-1)*7 = 182 ⇒ (n-1) = 26 ⇒ n = 27.

Q 3 - What number between 200 and 600 are distinct by 4, 5, 6?

Answer : B

Explanation

LCM of 4, 5, 6 = 2*2*5*3 = 60
So, each one must be divisible by 60.
Requisite numbers are 240, 300, 360, 420, 480 and 540.
Their no. is 6.

Q 4 - The total 5+6+7+8+.....+19=?

Answer : C

Explanation

This is an A.P. in which a = 5, d =1 and L=19.
Let the number of its term be n. Then,
Tṇ = 19 ⇒ a + (n-1) d =19
⇒ 5 + (n-1) * 1 = 19 ⇒ (n-1) =14 ⇒ n= 15.
∴ Sṇ = n/2 * (a+L) = 15/2 *(5+19) = 180.

Q 5 - The eighth term of the G.P. 2, 6, 18 ...is:

Answer : C

Explanation

Here a = 2 and r = 6/2 =3.
8th term = [a*r (⁸⁻ⁱ)] = ar ⁷ = 2*3⁷ = 2*(2187) = 4374

Q 6 - Which term of the G.P. 5,10,20,40 ...is 1280?

Answer : B

Explanation

Let T_n = 1280. Then ar (ⁿ⁻ⁱ) = 1280 ⇒ Here a= 5 and r =2
∴ 5*2(ⁿ⁻ⁱ) =1280 ⇒256 = 2(ⁿ⁻ⁱ) =2⁸ ⇒ n-1 =8 ⇒ n= 9

Q 7 - In the event that a ≠b, Then which of the accompanying proclamations is valid?

Answer : C

Explanation

For any two unequal numbers a and b, we have (A.M).> (g.m)
∴   (a+b)/2 > √ab

Q 8 - A whelp comprises of individuals whose ages are in A.P., the normal contrast being 3 months .If the most youthful of the club in not more than years old and the sum of the age of the considerable number of recollects is 250 years, then the no. of recall in the club is :

Answer : C

Explanation

Let the ages be 7 years, 29/4 years, 15/2 years and so on.
The ages are in A.P. in which a=7, d= 1/4 and Sn= 250
Sn = n/2[2a+ (n-1) d] ⇒ n/2 [2*7+ (n-1)*1/4] =250
⇒ n [14+ (n-1)/4] = 250
⇒ n [14+ (n-1)/4 ]=500 ⇒ n[56+(n-1) = 2000
⇒ n (n+55) = 2000 ⇒ n² +55n-2000 = 0
⇒ n²+80n -25n -2000 = 0 ⇒ n (n+80)-25 (n+80) = 0
⇒ (n+80) (n-25) = 0 ⇒ n= 25(∵ n ≠-80)
∴ Number of members in the club= 25

Q 9 - (1³ +2³ + 3³+...... + 15³) =?

Answer : D

Explanation

We know that (1³+2³+3³+??+n³) = {n (n-1)/2)²
∴ (1³+2³+3³+?..+15³) = (15*16/2)² = (120)² = 14400.³

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