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Progression - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Which term of the A.P. 2, 7, 12, 17...are 87?
Answer : C
Explanation
Here a =2, d= (7-2) =5. Let the nth term be 87. Then, a + (n-1) d =87 ⇒ 2+ (n-1)*5 = 87 ⇒ (n-1)*5= 85 ⇒ (n-1) = 17 ⇒ n = 18 ∴ 18th term is 87.
Q 2 - What number of numbers arrive somewhere around 10 and 200 which are precisely separable by 7?
Answer : D
Explanation
Requisite numbers are 14, 21, 28, 35 .., 196. This is an A.P. in which a = 14 and d = 7 a +(n-1) d = 196 ⇒ 14+(n-1)*7 =196 = (n-1)*7 = 182 ⇒ (n-1) = 26 ⇒ n = 27.
Answer : B
Explanation
LCM of 4, 5, 6 = 2*2*5*3 = 60 So, each one must be divisible by 60. Requisite numbers are 240, 300, 360, 420, 480 and 540. Their no. is 6.
Answer : C
Explanation
This is an A.P. in which a = 5, d =1 and L=19. Let the number of its term be n. Then, Tṇ = 19 ⇒ a + (n-1) d =19 ⇒ 5 + (n-1) * 1 = 19 ⇒ (n-1) =14 ⇒ n= 15. ∴ Sṇ = n/2 * (a+L) = 15/2 *(5+19) = 180.
Answer : C
Explanation
Here a = 2 and r = 6/2 =3. 8th term = [a*r (⁸⁻ⁱ)] = ar ⁷ = 2*3⁷ = 2*(2187) = 4374
Answer : B
Explanation
Let Tn = 1280. Then ar (ⁿ⁻ⁱ) = 1280 ⇒ Here a= 5 and r =2 ∴ 5*2(ⁿ⁻ⁱ) =1280 ⇒256 = 2(ⁿ⁻ⁱ) =2⁸ ⇒ n-1 =8 ⇒ n= 9
Q 7 - In the event that a ≠b, Then which of the accompanying proclamations is valid?
Answer : C
Explanation
For any two unequal numbers a and b, we have (A.M).> (g.m) ∴ (a+b)/2 > √ab
Q 8 - A whelp comprises of individuals whose ages are in A.P., the normal contrast being 3 months .If the most youthful of the club in not more than years old and the sum of the age of the considerable number of recollects is 250 years, then the no. of recall in the club is :
Answer : C
Explanation
Let the ages be 7 years, 29/4 years, 15/2 years and so on. The ages are in A.P. in which a=7, d= 1/4 and Sn= 250 Sn = n/2[2a+ (n-1) d] ⇒ n/2 [2*7+ (n-1)*1/4] =250 ⇒ n [14+ (n-1)/4] = 250 ⇒ n [14+ (n-1)/4 ]=500 ⇒ n[56+(n-1) = 2000 ⇒ n (n+55) = 2000 ⇒ n2 +55n-2000 = 0 ⇒ n2+80n -25n -2000 = 0 ⇒ n (n+80)-25 (n+80) = 0 ⇒ (n+80) (n-25) = 0 ⇒ n= 25(∵ n ≠-80) ∴ Number of members in the club= 25
Answer : D
Explanation
We know that (13+23+33+??+n3) = {n (n-1)/2)2 ∴ (13+23+33+?..+153) = (15*16/2)2 = (120)2 = 14400.3
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