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Aptitude - Arithmetic Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : C
Explanation
Here a = 3, d = 5 - 3 = 2, n = 16 Using formula Tn = a + (n - 1)d T16 = 3 + (16 - 1) x 2 = 33
Q 2 - The divisor is five times the quotient and five times the remainder. If the remainder is 29, the dividend is?
Answer : B
Explanation
Divisor = (5 x 29) = 145 = 5 x Quotient = Divisor => Quotient = 145/5 = 29 Dividend = (Divisor x Quotient) + Remainder Dividend = (145* 29) + 29 = 4234.
Q 3 - The difference between local and the face value of 8 in the numeral is 568012?
Answer : C
Explanation
8000 - 8 = 7992
Q 4 - If (28)3 is subtracted from the square of a number, the answer so obtained is 1457. What is the number?
Answer : D
Explanation
Let the number = x According to question, x2 - 283 = 1457 or, x = 153
Q 5 - How many multiples of 3 are available between 15 and 105 including both?
Answer : B
Explanation
Here numbers are 15, 18, ..., 105 which is an A.P. Here a = 15, d = 3, Using formula Tn = a + (n - 1)d T11 = 15 + (n - 1) x 3 = 105 => 12 + 3n = 105 => n = 93 / 3 = 31
Answer : B
Explanation
As a, a-2 and 3a are in an A.P. ∴ (a-2) - a = 3a - (a-2) => -2 = 2a - 2 => a = -2
Answer : A
Explanation
Here a = 3, r = 3 , Sn = 363 Using formula Sn = a(rn - 1) / (r-1) Sn = 3 x (3n - 1) / (3 - 1) = 363 => 3n - 1 = (363 x 2) / 3 => 3n = 243 = 35 => n = 5
Q 8 - If a clock buzzes 1 time at 1 o'clock , 2 times at 2 o'clock and so on then how many times it buzzes in a day?
Answer : C
Explanation
Total buzzes = 2(1 + 2 + 3 ... + 12) Here a = 1, d = 1 , l = 12 Using formula Sn = (n/2)[a+l] Sn = (12/2)[1+12] = 6 x 13 = 78 Thus total number of buzzes = 2 x 78 = 156.
Answer : D
Explanation
Here a = 3, d = 5 - 3 = 2, n = 18 Using formula Tn = a + (n - 1)d T18 = 3 + (18 - 1) x 2 = 37
Answer : B
Explanation
Here series is 12, 18, 24, ... 96. Here a = 12, d = 18 - 12 = 6 Using formula Tn = a + (n - 1)d Tn = 12 + (n - 1) x 6 = 96 => 12 + 6n - 6 = 96 => 6n = 90 => n = 15
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