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Python Pandas - Return a new Index with elements of index not in other but unsort the result
To return a new Index with elements of index not in other but unsort the result, use the difference() method. Set the sort parameter to False.
At first, import the required libraries −
import pandas as pd
Creating two Pandas index −
index1 = pd.Index([30, 10, 20, 50, 40]) index2 = pd.Index([80, 40, 60, 20, 55])
Display the Pandas index1 and index2 −
print("Pandas Index1...\n",index1)
print("Pandas Index2...\n",index2)Get the difference of both the indexes. Results are unsorted using the "sort" parameter with value "False" −
res = index1.difference(index2, sort=False)
Example
Following is the code −
import pandas as pd
# Creating two Pandas index
index1 = pd.Index([30, 10, 20, 50, 40])
index2 = pd.Index([80, 40, 60, 20, 55])
# Display the Pandas index1 and index2
print("Pandas Index1...\n",index1)
print("Pandas Index2...\n",index2)
# Return the number of elements in Index1 and Index2
print("\nNumber of elements in index1...\n",index1.size)
print("\nNumber of elements in index2...\n",index2.size)
# Get the difference of both the indexes
# Results are unsorted using the "sort" parameter with value "False"
res = index1.difference(index2, sort=False)
# Difference of both the indexes i.e. return a new Index with elements of index not in other
print("\nDifference...\n",res)Output
This will produce the following output −
Pandas Index1... Int64Index([30, 10, 20, 50, 40], dtype='int64') Pandas Index2... Int64Index([80, 40, 60, 20, 55], dtype='int64') Number of elements in index1... 5 Number of elements in index2... 5 Difference... Int64Index([30, 10, 50], dtype='int64')
Updated on: 14-Oct-2021
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