How to use variable arguments as an input when dealing with method overloading in Java

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Problem Description

How to use variable arguments as an input when dealing with method overloading?

Solution

This example displays how to overload methods which have variable arguments as an input.

public class Main {
   static void vaTest(int ... no) {
      System.out.print(
         "vaTest(int ...): " + "Number of args: " + no.length +" Contents: ");
      for(int n : no)System.out.print(n + " ");
      System.out.println();
   }
   static void vaTest(boolean ... bl) {
      System.out.print(
         "vaTest(boolean ...) " + "Number of args: " + bl.length + " Contents: ");
      for(boolean b : bl)System.out.print(b + " ");
      System.out.println();
   }
   static void vaTest(String msg, int ... no) {
      System.out.print(
         "vaTest(String, int ...): " + msg +"no. of arguments: "+ no.length +" Contents: ");
      for(int  n : no)
      System.out.print(n + " ");
      System.out.println();
   }
   public static void main(String args[]) {
      vaTest(1, 2, 3);
      vaTest("Testing: ", 10, 20);
      vaTest(true, false, false);
   }
}

Result

The above code sample will produce the following result.

vaTest(int ...): Number of args: 3 Contents: 1 2 3 
vaTest(String, int ...): Testing: no. of arguments: 2 
Contents: 10 20 
vaTest(boolean ...) Number of args: 3 Contents: 
true false false 

The following is an another sample example of varargs with method overloading.

public class Vararg {
   static void vararg(Integer... x) {
      System.out.println("Integer..."); 
   } 
   static void vararg(String... x) {
      System.out.println("String..."); 
   }
   public static void main(String [] args) {
      int s = 0;
      vararg(s,s);
   }
}

The above code sample will produce the following result.

Integer...