Java - Tutorial

How to use handle the exception methods in Java

Problem Description:

How to use handle the exception methods?

Solution:

This example shows how to handle the exception methods by using System.err.println() method of System class .

public class Main{
   public static void main (String args[]){
      int array[]={20,20,40};
      int num1=15,num2=10;
      int result=10;
      try{
         result = num1/num2;
         System.out.println("The result is" +result);
         for(int i =5;i >=0; i--){
            System.out.println("The value of array is" +array[i]);
         }
      }
      catch (ArrayIndexOutOfBoundsException e){
         System.out.println("Array is out of Bounds"+e);
      }
      catch (ArithmeticException e){
         System.out.println ("Can't divide by Zero"+e);
      }
   }
}

Result:

The above code sample will produce the following result.

The result is1
Array is out of Boundsjava.lang.ArrayIndexOutOfBoundsException: 5

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