How to search an element inside a linked list ?
Following example demonstrates how to search an element inside a linked list using linkedlistname.indexof(element) to get the first position of the element and linkedlistname.Lastindexof(elementname) to get the last position of the element inside the linked list.
import java.util.LinkedList; public class Main { public static void main(String[] args) { LinkedList<String> lList = new LinkedList<String>(); lList.add("1"); lList.add("2"); lList.add("3"); lList.add("4"); lList.add("5"); lList.add("2"); System.out.println("First index of 2 is:"+ lList.indexOf("2")); System.out.println("Last index of 2 is:"+ lList.lastIndexOf("2")); } }
The above code sample will produce the following result.
First index of 2 is: 1 Last index of 2 is: 5
The following is an another example to search an element inside a linked list.
import java.util.LinkedList; public class Demo { public static void main(String args[]) { LinkedList<Integer> linkedlist1 = new LinkedList<>(); linkedlist1.add(001); linkedlist1.add(002); linkedlist1.add(003); linkedlist1.add(004); linkedlist1.add(005); linkedlist1.add(003); System.out.println("First index of 004 is : " + linkedlist1.indexOf(004)); System.out.println("Last index of 004 is : " + linkedlist1.lastIndexOf(004)); } }
The above code sample will produce the following result.
First index of 004 is : 3 Last index of 004 is : 3