Java Examples - Search min and max

Problem Description

How to search the minimum and the maximum element in an array ?

Solution

This example shows how to search the minimum and maximum element in an array by using Collection.max() and Collection.min() methods of Collection class .

```import java.util.Arrays;
import java.util.Collections;

public class Main {
public static void main(String[] args) {
Integer[] numbers = { 8, 2, 7, 1, 4, 9, 5};
int min = (int) Collections.min(Arrays.asList(numbers));
int max = (int) Collections.max(Arrays.asList(numbers));

System.out.println("Min number: " + min);
System.out.println("Max number: " + max);
}
}
```

Result

The above code sample will produce the following result.

```Min number: 1
Max number: 9
```

Another sample example of the minimum and the maximum element in an array.

```public class HelloWorld {
public static void main(String[] args) {
int numbers[] = new int[]{8, 2, 7, 1, 4, 9, 5};
int s = numbers[0];
int l = numbers[0];

for(int i = 1; i < numbers.length; i++) {
if(numbers[i] > l)l = numbers[i];
else if (numbers[i] < s)s = numbers[i];
}
System.out.println("Largest Number is : " + l);
System.out.println("Smallest Number is : " + s);
}
}
```

The above code sample will produce the following result.

```Largest Number is : 9
Smallest Number is : 1
```
java_arrays.htm