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Java Examples - Search min and max
Problem Description
How to search the minimum and the maximum element in an array ?
Solution
This example shows how to search the minimum and maximum element in an array by using Collection.max() and Collection.min() methods of Collection class .
import java.util.Arrays; import java.util.Collections; public class Main { public static void main(String[] args) { Integer[] numbers = { 8, 2, 7, 1, 4, 9, 5}; int min = (int) Collections.min(Arrays.asList(numbers)); int max = (int) Collections.max(Arrays.asList(numbers)); System.out.println("Min number: " + min); System.out.println("Max number: " + max); } }
Result
The above code sample will produce the following result.
Min number: 1 Max number: 9
Another sample example of the minimum and the maximum element in an array.
public class HelloWorld { public static void main(String[] args) { int numbers[] = new int[]{8, 2, 7, 1, 4, 9, 5}; int s = numbers[0]; int l = numbers[0]; for(int i = 1; i < numbers.length; i++) { if(numbers[i] > l)l = numbers[i]; else if (numbers[i] < s)s = numbers[i]; } System.out.println("Largest Number is : " + l); System.out.println("Smallest Number is : " + s); } }
The above code sample will produce the following result.
Largest Number is : 9 Smallest Number is : 1
java_arrays.htm
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