Java Examples - Search min and max

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Problem Description

How to search the minimum and the maximum element in an array ?

Solution

This example shows how to search the minimum and maximum element in an array by using Collection.max() and Collection.min() methods of Collection class .

import java.util.Arrays;
import java.util.Collections;

public class Main {
   public static void main(String[] args) {
      Integer[] numbers = { 8, 2, 7, 1, 4, 9, 5};
      int min = (int) Collections.min(Arrays.asList(numbers));
      int max = (int) Collections.max(Arrays.asList(numbers));
      
      System.out.println("Min number: " + min);
      System.out.println("Max number: " + max);
   }
}

Result

The above code sample will produce the following result.

Min number: 1
Max number: 9

Another sample example of the minimum and the maximum element in an array.

public class HelloWorld {
   public static void main(String[] args) {
      int numbers[] = new int[]{8, 2, 7, 1, 4, 9, 5};
      int s = numbers[0];
      int l = numbers[0];
      
      for(int i = 1; i < numbers.length; i++) {
         if(numbers[i] > l)l = numbers[i];
         else if (numbers[i] < s)s = numbers[i];
      } 
      System.out.println("Largest Number is : " + l);
      System.out.println("Smallest Number is : " + s);
   }
}

The above code sample will produce the following result.

Largest Number is : 9
Smallest Number is : 1