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Javax.xml.parsers.SAXParser.parse() Method
Description
The Javax.xml.parsers.SAXParser.parse(String uri, HandlerBase hb) method parses the content described by the giving Uniform Resource Identifier (URI) as XML using the specified HandlerBase.
Declaration
Following is the declaration for Javax.xml.parsers.SAXParser.parse() method
public void parse(String uri, HandlerBase hb)
Parameters
uri − The location of the content to be parsed.
hb − The SAX HandlerBase to use.
Return Value
This method does not return a value.
Exception
IllegalArgumentException − If uri is null
IOException − If any IO errors occur.
SAXException − If any SAX errors occur during processing.
Example
For our examples to work, a xml file named Student.xml is needed in our CLASSPATH. The contents of this XML are the following −
<?xml version = "1.0" encoding = "UTF-8" standalone = "yes"?> <student id = "10"> <age>12</age> <name>Malik</name> </student>
The following example shows the usage of Javax.xml.parsers.SAXParser.parse() method.
package com.tutorialspoint; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.HandlerBase; public class SaxParserDemo { public static void main(String[] args) { // create a new SAXParserFactory SAXParserFactory factory = SAXParserFactory.newInstance(); // create a new DefaultHandler HandlerBase handler = new HandlerBase() { // define what the parser does when it finds a character public void characters(char[] ch, int start, int length) { // print the characters System.out.println("" + new String(ch, start, length)); } }; try { // get a new SAXParser SAXParser parser = factory.newSAXParser(); // parse the file parser.parse("Student.xml", handler); } catch (Exception ex) { ex.printStackTrace(); } } }
If we compile the code and execute it, this will produce the following result −
12 Malik
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