- Java.util Package Classes
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- Java.util Package Extras
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- Java.util - Discussion
Java LinkedList spliterator() Method
Description
The Java LinkedList spliterator() method creates a late-binding and fail-fast Spliterator for the elements in this linkedList. Late binding means the spliterator binds to the source of elements at the time of traversal and not when it is created. Spliterator is a better iterator and provides more controls over items during traversal.
Declaration
Following is the declaration for java.util.LinkedList.spliterator() method
public Spliterator<E> spliterator()
Parameters
NA
Return Value
This method returns a Spliterator over the elements in this list in proper sequence.
Exception
NA
Getting Spliterator of the LinkedList of Integers Example
The following example shows the usage of Java LinkedList spliterator() method. We're creating a LinkedList of Integers. We're adding couple of Integers to the LinkedList object using add() method calls per element and using spliterator() method, we're iterating the list and print all the elements.
package com.tutorialspoint; import java.util.LinkedList; import java.util.Spliterator; public class LinkedListDemo { public static void main(String[] args) { // create an empty linked list LinkedList<Integer> linkedList = new LinkedList<>(); // use add() method to add elements in the linkedList linkedList.add(0); linkedList.add(1); linkedList.add(2); linkedList.add(3); linkedList.add(4); linkedList.add(5); linkedList.add(6); Spliterator<Integer> spliterator = linkedList.spliterator(); spliterator.forEachRemaining(i -> System.out.println(i)); } }
Output
Let us compile and run the above program, this will produce the following result −
0 1 2 3 4 5 6
Getting Spliterator of the LinkedList of Integers Example
The following example shows the usage of Java LinkedList Spliterator() method. We're creating a LinkedList of Strings. We're adding couple of Strings to the LinkedList object using add() method calls per element and using Spliterator() method, we're iterating the list and print all the elements.
package com.tutorialspoint; import java.util.LinkedList; import java.util.Spliterator; public class LinkedListDemo { public static void main(String[] args) { // create an empty linked list LinkedList<String> linkedList = new LinkedList<>(); // use add() method to add elements in the linkedList linkedList.add("A"); linkedList.add("B"); linkedList.add("C"); linkedList.add("D"); linkedList.add("E"); linkedList.add("F"); Spliterator<String> spliterator = linkedList.spliterator(); spliterator.forEachRemaining(i -> System.out.println(i)); } }
Output
Let us compile and run the above program, this will produce the following result −
A B C D E F
Getting Spliterator of the LinkedList of Integers Example
The following example shows the usage of Java LinkedList spliterator() method. We're creating a LinkedList of Student objects. We're adding couple of Student objects to the LinkedList object using add() method calls per element and using spliterator() method, we're iterating the list and print all the elements.
package com.tutorialspoint; import java.util.LinkedList; import java.util.Spliterator; public class LinkedListDemo { public static void main(String[] args) { // create an empty linkedList LinkedList<Student> linkedList = new LinkedList<>(); // use add() method to add elements in the linkedList linkedList.add(new Student(1, "Julie")); linkedList.add(new Student(2, "Robert")); linkedList.add(new Student(3, "Adam")); Spliterator<Student> spliterator = linkedList.spliterator(); spliterator.forEachRemaining(i -> System.out.println(i)); } } class Student { int rollNo; String name; Student(int rollNo, String name){ this.rollNo = rollNo; this.name = name; } @Override public String toString() { return "[ " + this.rollNo + ", " + this.name + " ]"; } @Override public boolean equals(Object obj) { Student s = (Student)obj; return this.rollNo == s.rollNo && this.name.equalsIgnoreCase(s.name); } }
Output
Let us compile and run the above program, this will produce the following result −
[ 1, Julie ] [ 2, Robert ] [ 3, Adam ]
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