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- Java.util - LinkedHashMap
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Java LinkedHashMap containsValue() Method
Description
The Java LinkedHashMap containsValue(Object value) method returns true if this map maps one or more keys to the specified value.
Declaration
Following is the declaration for java.util.LinkedHashMap.containsValue() method
public boolean containsValue(Object value)
Parameters
value − value whose presence in this map is to be tested
Return Value
This method returns true if this map maps one or more keys to the specified value
Exception
NA
Checking a Value to be Present in a LinkedHashMap of Integer, Integer Pair Example
The following example shows the usage of Java LinkedHashMap containsValue() method to check if a value is present in a Map or not. We've created a Map object of Integer,Integer pair. Then few entries are added, map is printed and using containsValue() we're checking about two values in the map.
package com.tutorialspoint;
import java.util.LinkedHashMap;
public class LinkedHashMapDemo {
public static void main(String args[]) {
// create hash map
LinkedHashMap<Integer,Integer> newmap = new LinkedHashMap<>();
// populate hash map
newmap.put(1, 1);
newmap.put(2, 2);
newmap.put(3, 3);
System.out.println("Initial map elements: " + newmap);
System.out.println("Map contains 2 as value: " + newmap.containsValue(2));
System.out.println("Map contains 4 as value: " + newmap.containsValue(4));
}
}
Output
Let us compile and run the above program, this will produce the following result.
Initial map elements: {1=1, 2=2, 3=3}
Map contains 2 as value: true
Map contains 4 as value: false
Checking a Value to be Present in a LinkedHashMap of Integer, String Pair Example
The following example shows the usage of Java LinkedHashMap containsValue() method to check if a value is present in a Map or not. We've created a Map object of Integer,String pair. Then few entries are added, map is printed and using containsValue() we're checking about two values in the map.
package com.tutorialspoint;
import java.util.LinkedHashMap;
public class LinkedHashMapDemo {
public static void main(String args[]) {
// create hash map
LinkedHashMap<Integer,String> newmap = new LinkedHashMap<>();
// populate hash map
newmap.put(1, "tutorials");
newmap.put(2, "point");
newmap.put(3, "is best");
System.out.println("Initial map elements: " + newmap);
System.out.println("Map contains tutorials as value: " + newmap.containsValue("tutorials"));
System.out.println("Map contains java as value: " + newmap.containsValue("java"));
}
}
Output
Let us compile and run the above program, this will produce the following result.
Initial map elements: {1=tutorials, 2=point, 3=is best}
Map contains tutorials as value: true
Map contains java as value: false
Checking a Value to be Present in a LinkedHashMap of Integer, Object Pair Example
The following example shows the usage of Java LinkedHashMap containsValue() method to check if a value is present in a Map or not. We've created a Map object of Integer,Student pair. Then few entries are added, map is printed and using containsValue() we're checking about two values in the map.
package com.tutorialspoint;
import java.util.LinkedHashMap;
public class LinkedHashMapDemo {
public static void main(String args[]) {
// create hash map
LinkedHashMap<Integer,Student> newmap = new LinkedHashMap<>();
// populate hash map
newmap.put(1, new Student(1, "Julie"));
newmap.put(2, new Student(2, "Robert"));
newmap.put(3, new Student(3, "Adam"));
System.out.println("Initial map elements: " + newmap);
System.out.println("Map contains Robert as value: " + newmap.containsValue(new Student(2, "Robert")));
System.out.println("Map contains Jene as value: " + newmap.containsValue(new Student(4, "Jene")));
}
}
class Student {
int rollNo;
String name;
Student(int rollNo, String name){
this.rollNo = rollNo;
this.name = name;
}
@Override
public String toString() {
return "[ " + this.rollNo + ", " + this.name + " ]";
}
@Override
public boolean equals(Object obj) {
if(obj == null) return false;
Student s = (Student)obj;
return this.rollNo == s.rollNo && this.name.equalsIgnoreCase(s.name);
}
}
Output
Let us compile and run the above program, this will produce the following result.
Initial map elements: {1=[ 1, Julie ], 2=[ 2, Robert ], 3=[ 3, Adam ]}
Map contains Robert as value: true
Map contains Jene as value: false