How to list the hidden files in a directory in Java?

JavaServer Side ProgrammingProgramming

The ListFiles() method returns an array holding the objects (abstract paths) of all the files (and directories) in the path represented by the current (File) object.

The File Filter interface is filter for the path names you can pass this as a parameter to the listFiles() method. This method filters the file names passed on the passed filter.

To get the hidden directories in a folder, implement a FileFilter which accepts only hidden directories, and pass it as a parameter to the listFiles() method.

Example

import java.io.File;
import java.io.FileFilter;
import java.io.IOException;
public class Test{
   public static void main(String args[]) throws IOException {
    //Creating a File object for directory
    File directoryPath = new File("D:\\ExampleDirectory");
    //Creating filter for directories files
    FileFilter fileFilter = new FileFilter(){
         public boolean accept(File dir) {          
            if (dir.isDirectory()&& dir.isHidden()) {
               return true;
            } else {
               return false;
            }
         }
      };        
      File[] list = directoryPath.listFiles(fileFilter);
      System.out.println("List of the jpeg files in the specified directory:");  
      for(File fileName : list) {
         System.out.println(fileName.getName());
         System.out.println(fileName);
      }  
   }
}

Output

List of the jpeg files in the specified directory:
hidden directory1
D:\ExampleDirectory\hidden directory1
hidden directory2
D:\ExampleDirectory\hidden directory2

We can also get the list of hidden files using the is Hidden() method of the Files class −

Example

import java.io.File;
import java.io.IOException;
import java.util.Arrays;
import java.util.stream.Stream;
public class Demo {
   public static void main(String[] args) throws IOException {
       File dir = new File("D:\\ExampleDirectory");
       File[] files = dir.listFiles(File::isHidden);
       Stream <File> fileStream = Arrays.stream(files);
       fileStream.forEach(file -> System.out.println(file.getName()));
    }
}

Output

D:\ExampleDirectory\hidden directory1
D:\ExampleDirectory\hidden directory2
raja
Published on 08-Feb-2021 11:19:31
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