How to get the ownership control details of an S3 bucket using Boto3 and AWS Client?

Boto3PythonServer Side ProgrammingProgramming

Problem Statement − Use boto3 library in Python to get ownership control detail of a S3 bucket.

For example, find the ownership control detail of Bucket_1 in S3.

Approach/Algorithm to solve this problem

Step 1 − Import boto3 and botocore exceptions to handle exceptions.

Step 2 − Use bucket_name as the parameter in the function.

Step 3 − Create an AWS session using boto3 library.

Step 4 − Create an AWS client for S3.

Step 5 − Now use the function get_bucket_ownership_controls and pass the bucket name.

Step 6 − It returns the dictionary containing the details about S3.

Step 7 − Handle the generic exception if something went wrong while deleting the file.

Example

Use the following code to get ownership detail of a bucket −

import boto3
from botocore.exceptions import ClientError

def get_bucket_ownership_control_of_s3(bucket_name):
   session = boto3.session.Session()
   s3_client = session.client('s3')
   try:
      result = s3_client.get_bucket_ownership_controls(Bucket=bucket_name,)
   except ClientError as e:
      raise Exception( "boto3 client error in get_bucket_ownership_control_of_s3: " + e.__str__())
   except Exception as e:
      raise Exception( "Unexpected error in get_bucket_ownership_control_of_s3: " + e.__str__())
   return result

print(get_bucket_ownership_control_of_s3("Bucket_1"))

Output

{
   'OwnershipControls': {
      'Rules': [
         {
            'ObjectOwnership': 'BucketOwnerPreferred'|'ObjectWriter'
         },
      ]
   }
}
raja
Published on 22-Mar-2021 07:58:58
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