Ayush Gupta

Ayush Gupta

433 Articles Published

Articles by Ayush Gupta

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Program to find Sum of a Series a^1/1! + a^2/2! + a^3/3! + a^4/4! +.......+ a^n/n! in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 665 Views

In this problem, we are given two numbers a and n. Our task is to create a program to find Sum of a Series a^1/1! + a^2/2! + a^3/3! + a^4/4! +…….+ a^n/n! in C++.Problem description − The problem is to find the sum of the given series using the given values of a and n. The series is a special series in which each term is the multiple of the last term with a/i, i -> 1 to n.Let’s take an example to understand the problemInputa = 3, n = 4Output15.375Explanationsum of series is(3^1)/1! + (3^2)/2! + (3^3)/3! + ...

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Program to find sum of elements in a given array in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 1K+ Views

In this problem, we are given an array arr[] of n integer values. Our task is to create a Program to find sum of elements in a given array in C++.Program Description − For the given array, we will add up all elements and return the sum.Let’s take an example to understand the problemInputarr[] = {3, 1, 7, 2, 9, 10}Output32ExplanationSum = 3 + 1 + 7 + 2 + 9 + 10 = 32Solution ApproachTo find the sum of elements of the array, we will traverse the array and extract each element of the array and add them to ...

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Program to find sum of first n natural numbers in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 451 Views

In this tutorial, we will be discussing a program to find sum of first n natural numbers.For this we will be provided with an integer n. Our task is to add up, find the sum of the first n natural numbers and print it out.Example#include using namespace std; //returning sum of first n natural numbers int findSum(int n) {    int sum = 0;    for (int x=1; x

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Program to find sum of harmonic series in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 1K+ Views

In this problem, we are given three numbers a, d, and n. Our task is to create a program to find sum of harmonic series in C++.Harmonic progression is a series whose inverse will be an arithmetic progression. I.e. if for a harmonic progression A1, A2, A3.. An, there is an arithmetic progression 1/A1, 1/A2, 1/A3.So, a general HP is1/a, 1/(a+d), 1/(a+2d), … 1/(a + nd)Where 1/a is the first term. And d is the common difference of the reversed AP.Problem Description − Here, we will be given the first term a, common difference d, and the number of terms ...

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Program to find sum of series 1 + 1/2 + 1/3 + 1/4 + .. + 1/n in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 4K+ Views

In this problem, we are given a number n. Our task is to create a program to find sum of series 1 + 1/2 + 1/3 + 1/4 + .. + 1/n in C++.Code description − Here, we will find the sum of the series 1 + 1/2 + 1/3 + 1/4 + .. + 1/n till nth term. The series is a harmonic progression series.Harmonic progression is a series whose inverse will be an arithmetic progression. I.e. if for a harmonic progression A1, A2, A3... An, there is an arithmetic progression 1/A1, 1/A2, 1/A3.First, let’s take an example to ...

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Program to find the angles of a quadrilateral in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 313 Views

In this problem, we are given a value d, which is the common difference of AP. This AP is all the angles of a quadrilateral. Our task is to create a program to find the angles of a quadrilateral in C++.Problem Description − Here, the angles of the quadrilateral are in the form of an AP with common difference d. And we need to find the angles.Let’s take an example to understand the problemInputd = 15Output67.5, 82.5, 97.5, 112.5ExplanationFirst angle is x Second angle is x + 15 Third angle is x + 30 Four angle is x + 45Sum ...

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Program to find Prime Numbers Between given Interval in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 376 Views

In this tutorial, we will be discussing a program to find prime numbers between given intervals.For this we would be provided with two integers. Our task is to find the prime numbers in that particular range.Example#include using namespace std; int main() {    int a, b, i, j, flag;    //getting lower range    a = 3;    //getting upper range    b = 12;    cout

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Program to find remainder when large number is divided by 11 in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 531 Views

In this problem, we are given a string num which is a large number. Our task is to create a program to find remainder when large number is divided by 11 in C++.Problem Description − We need to find the remainder when the number defined by the string is divided by 11.Let’s take an example to understand the problemInputnum = “43212981843718452”Output7Solution ApproachTo find the remainder, we obviously need to divide the number. But dividing huge number is a complex process so to ease up the process, we will divide digit by digit. And store the remainder that follows. This process ...

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Program to find remainder when large number is divided by r in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 573 Views

In this problem, we are given a string num which is a large number and an integer R. Our task is to create a program to find remainder when large number is divided by r in C++.Problem Description − We need to find the remainder when the number defined by the string is divided by r which is a two-digit number.Let’s take an example to understand the problemInputnum = “123423450942121” r = 54Output7Solution ApproachTo find the remainder, we obviously need to divide the number. But dividing huge numbers is a complex process so to ease up the process, we will ...

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Program to find remainder without using modulo or % operator in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 2K+ Views

In this problem, we are given two numbers, N and D. Our task is to create a Program to find remainder without using modulo or % operator in C++.Problem description − We need to find the remainder that will be left after dividing the number N by D. But we cannot use the modulo or % operator for this.Let’s take an example to understand the problemInputN = 53 D = 3Output2Solution ApproachTo find the remainder, a simple approach is to find the number less than N which is the multiple of D. And the substrate the number from N. To ...

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